https://file.aiquickdraw.com/mathbot/file/1728977651840mhi2bcmr.jpg

The text in the image asks:

"In the tennis club's third-year group, there are 4 boys and 6 girls. When one boy and one girl are selected for a duty position, how many ways can this selection be made?"

The options provided are:

- A. 12
- B. 24
- C. 48
- D. 80
- E. 120

### Solution:
You are asked to choose one boy and one girl. The total number of ways to select one boy and one girl is the product of the number of boys and girls available.

There are:
- 4 boys
- 6 girls

To find the total number of ways to make this selection, multiply the number of boys and girls:

\[
\text{Total number of ways} = 4 \times 6 = 24
\]

Thus, the correct answer is **B. 24**.

Would you like further details on this explanation, or do you have any questions?

Here are some related questions to expand on this:

1. How would the answer change if there were 5 boys and 7 girls?
2. What if you needed to select 2 boys and 2 girls for different roles?
3. How does this type of combination problem relate to probability?
4. How many ways are there to select 2 boys and 1 girl from the group?
5. What if the selection required choosing 3 students regardless of gender?

**Tip:** For selection problems, always start by determining how many options there are for each individual choice, then multiply the possibilities when appropriate.

テニス部の3年生には、男子が4人、女子が6人所属している。男子、女子から一人ずつ掃除当番を選ぶ時、その選び方は何通りか。

Learn how to solve a combinatorics problem by selecting 1 boy and 1 girl from a group of 4 boys and 6 girls. Using the multiplication principle, find the total number of ways to make the selection. Suitable for students in Grades 6-8.

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