Math Problem Statement
In how many ways can 21 people form a circle with 10 members such that Juan and Pedro, belong to 21 people, insist that they always belong to the circle and never be separated?
Solution
We are given a group of 21 people, and we need to form a circular arrangement of 10 members, ensuring that Juan and Pedro are always included together.
Step 1: Treat Juan and Pedro as a Single Unit
Since Juan and Pedro insist on always being together, we can consider them as a single entity or a "super person." This effectively reduces the total number of people from 21 to 20.
Step 2: Selecting Members
We need to select 8 more people (since Juan and Pedro already take up 2 spots) from the remaining 19 people (since we grouped Juan and Pedro as one unit). The number of ways to choose these 8 members is:
Step 3: Arranging the Members in a Circle
For a circular arrangement, the number of ways to arrange 10 members (including Juan and Pedro as a unit) is:
since circular permutations of elements are counted as to avoid identical rotations being counted multiple times.
Step 4: Accounting for Juan and Pedro's Order
Since Juan and Pedro are treated as a single entity but can switch places within their unit, we must multiply by 2! to account for their internal arrangement.
Final Calculation:
This gives the total number of ways to form and arrange the circle while keeping Juan and Pedro together.
Would you like a step-by-step numerical evaluation of this formula? Let me know if anything needs clarification!
Related Questions:
- How would the solution change if Juan and Pedro could be separated?
- What if the arrangement was a line instead of a circle?
- How many ways could we form a circle of 15 members with the same constraints?
- What if three specific people had to be together instead of just Juan and Pedro?
- How does the formula change if order within the circle mattered (i.e., if the arrangement was not rotationally symmetric)?
Math Tip:
When dealing with circular permutations, always remember to subtract 1 from the number of elements before applying factorials, since rotations of the same arrangement are considered identical.
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Circular Permutations
Formulas
nCr = n! / (r! * (n-r)!)
(n-1)!
2!
Theorems
Circular permutations
Combination formula
Suitable Grade Level
Grades 10-12
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