Math Problem Statement

Simplify \( \frac{6!}{2!(6-2)!} \) and find its value.

Solution

The given mathematical expression is:

6!2!(62)!\frac{6!}{2!(6 - 2)!}

This is a permutation or combination formula. Specifically, it represents a combination, calculated as:

(62)=6!2!(62)!\binom{6}{2} = \frac{6!}{2!(6-2)!}

Step-by-Step Solution:

  1. Factorials:

    • 6!=6×5×4×3×2×1=7206! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720
    • 2!=2×1=22! = 2 \times 1 = 2
    • (62)!=4!=4×3×2×1=24(6-2)! = 4! = 4 \times 3 \times 2 \times 1 = 24
  2. Substitute values into the formula: 6!2!(62)!=7202×24\frac{6!}{2!(6-2)!} = \frac{720}{2 \times 24}

  3. Simplify the denominator:

    • 2×24=482 \times 24 = 48
  4. Divide: 72048=15\frac{720}{48} = 15

Final Answer:

6!2!(62)!=15\frac{6!}{2!(6-2)!} = 15

This represents the number of ways to choose 2 items from a set of 6.

Would you like further explanation or clarification?


Related Questions:

  1. What does the factorial symbol (!) mean in mathematics?
  2. How is this formula used in real-world applications like probability or statistics?
  3. Can you demonstrate how this relates to permutations instead of combinations?
  4. What happens if we calculate (63)\binom{6}{3} instead?
  5. How can this formula be generalized for any nn and rr?

Tip:

Always simplify factorials early to avoid unnecessary large multiplications.

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Math Problem Analysis

Mathematical Concepts

Factorials
Combinations
Permutations

Formulas

nCr = \frac{n!}{r!(n-r)!}
Factorial definition: n! = n × (n-1) × ... × 1

Theorems

Combination formula

Suitable Grade Level

Grades 9-12