To find \( 6! \times 2! \), let’s first calculate \( 6! \) and \( 2! \):

1. \( 6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720 \)
2. \( 2! = 2 \times 1 = 2 \)

Now, multiply these results:

\[
6! \times 2! = 720 \times 2 = 1440
\]

So, \( 6! \times 2! = 1440 \).

Would you like more details or have any questions?

### Related Questions
1. How do factorials work, and what is their purpose?
2. What is the result of dividing \( 6! \) by \( 2! \)?
3. How would \( 6! + 2! \) compare to \( 6! \times 2! \)?
4. What is \( 7! \) and how does it relate to \( 6! \)?
5. Can you explain why \( 0! = 1 \)?

### Tip
Factorials grow very quickly, so operations with them often lead to large numbers.

Discover how to solve the factorial multiplication problem 6! × 2! with a detailed breakdown. This problem involves calculating 6! and 2! before multiplying the results, a concept relevant to high school math. Suitable for students in Grades 9-10.

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