Math Problem Statement

Two girls were selling candy. They have $1.07 in change to begin. Their first customer said that before he could buy anything, he needed change for half a dollar. One of the girls looked and said that they didn't have the change. Then the customer asked if they had change for a quarter, but again, no. The customer asked if they had change for a dime- the answer was again no. The girls said they didn't even have change for a nickel. If they have 7 coins, what are they?

Solution

Let's analyze the problem step by step, focusing on the key information given:

  1. Total Value: The girls have a total of $1.07.
  2. Coins: They have 7 coins in total.
  3. No Change for Half a Dollar: This means they don't have enough coins (or the right combination of coins) to give 50 cents.
  4. No Change for a Quarter: They can't make 25 cents with their coins.
  5. No Change for a Dime: They can't make 10 cents with their coins.
  6. No Change for a Nickel: They can't make 5 cents with their coins.

Key Observations:

  • They have 7 coins, and the total is $1.07.
  • No combinations of their coins can add up to 50 cents, 25 cents, 10 cents, or 5 cents. This means they probably don't have any nickels, dimes, or quarters.
  • The only coin that they could still have is pennies (1 cent) and one dollar coin ($1).

Deduction:

If they can't make change for a nickel, it suggests that none of the coins are nickels or smaller multiples of 5 (which would be consistent with dimes and quarters as well). Therefore, the coins are likely:

  • 1 dollar coin (worth $1.00)
  • 6 pennies (worth 6 cents)

This gives a total of:

1 dollar+6×1 cent=1.00+0.06=1.061 \text{ dollar} + 6 \times 1 \text{ cent} = 1.00 + 0.06 = 1.06

But they need $1.07, so something is off. Let me reconsider the scenario to make sure we cover the final

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Math Problem Analysis

Mathematical Concepts

Logical Reasoning
Combinatorics
Currency Denominations

Formulas

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Theorems

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Suitable Grade Level

Grades 5-7