Math Problem Statement

2 4 6 8 1 4 7 10 13 16 19 data Frequency [Graphs generated by this script: setBorder(47,40,20,5); initPicture(0,19,0,9);axes(1000,2,1,1000,2); fill="blue"; stroke="black";line([1,-0.18],[1,0.18]); text([1,0],"1","below");line([4,-0.18],[4,0.18]); text([4,0],"4","below");line([7,-0.18],[7,0.18]); text([7,0],"7","below");line([10,-0.18],[10,0.18]); text([10,0],"10","below");line([13,-0.18],[13,0.18]); text([13,0],"13","below");line([16,-0.18],[16,0.18]); text([16,0],"16","below");line([19,-0.18],[19,0.18]); text([19,0],"19","below");textabs([165,0],"data","above");textabs([0,115],"Frequency","right",90);rect([1,0],[4,7]);rect([4,0],[7,9]);rect([7,0],[10,3]);rect([10,0],[13,2]);rect([13,0],[16,4]);rect([16,0],[19,6]);]

Based on the histogram above, what is the class width?

Class width =

What is the sample size?

Solution

To determine the class width and sample size from the histogram based on the given information, we follow these steps:

1. Class Width

The class width is the difference between the lower boundaries (or the upper boundaries) of consecutive classes.

From the information provided:

  • The first class is from 1 to 4
  • The second class is from 4 to 7
  • The third class is from 7 to 10, and so on.

To find the class width, subtract the lower boundary of the first class from the lower boundary of the second class: Class width=41=3\text{Class width} = 4 - 1 = 3

2. Sample Size

The sample size is the total frequency, which is the sum of all the frequencies for each class.

The frequencies provided (as per the rectangles' heights) are:

  • First class (1 to 4): Frequency = 7
  • Second class (4 to 7): Frequency = 9
  • Third class (7 to 10): Frequency = 3
  • Fourth class (10 to 13): Frequency = 2
  • Fifth class (13 to 16): Frequency = 4
  • Sixth class (16 to 19): Frequency = 6

Adding these frequencies gives the total sample size: Sample size=7+9+3+2+4+6=31\text{Sample size} = 7 + 9 + 3 + 2 + 4 + 6 = 31

Final Answers:

  • Class width = 3
  • Sample size = 31

Do you want more details or have any questions?

Related Questions:

  1. How would the histogram look if the class width were 5 instead of 3?
  2. What would happen to the sample size if one of the frequencies increased by 5?
  3. How do you interpret the shape of this histogram in terms of data distribution?
  4. How can you determine the mode from this histogram?
  5. How would you calculate the relative frequency for each class in this histogram?

Tip:

When interpreting histograms, always start by identifying the class intervals and their frequencies; this will help you quickly understand the distribution of your data.

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Math Problem Analysis

Mathematical Concepts

Statistics
Histograms
Frequency Distribution

Formulas

Class width = Upper boundary of a class - Lower boundary of the previous class
Sample size = Sum of all frequencies

Theorems

None specific; general principles of statistical data representation

Suitable Grade Level

Grades 6-8