Math Problem Statement

Scientists have recently discovered a strange new material called joelium, an electrical conductor whose mobile charges are joelons instead of electrons. The joelon has a charge of 3 times that of the electron and a mass of 7.88 times that of the electron. Assuming the other constants are the same:

What is the charge mobility of joelium relative to an ordinary conductor?

What is the conductivity of joelium relative to an ordinary conductor?

Solution

To address the questions, we will calculate the relative charge mobility and conductivity of joelium compared to an ordinary conductor. We'll base our calculations on the relationship between charge mobility, conductivity, and the properties of joelons versus electrons.

1. Charge Mobility of Joelium Relative to an Ordinary Conductor

Charge mobility (μ\mu) is defined as the drift velocity per unit electric field:

μ=vdE\mu = \frac{v_d}{E}

Mobility is inversely proportional to the mass of the charge carrier and directly proportional to the charge:

μqm\mu \propto \frac{q}{m}

Where:

  • qq is the charge of the carrier,
  • mm is the mass of the carrier.

For joelons compared to electrons:

  • The charge of a joelon is 3×3 \times the charge of an electron, i.e., qj=3qeq_j = 3q_e,
  • The mass of a joelon is 7.88×7.88 \times the mass of an electron, i.e., mj=7.88mem_j = 7.88m_e.

Thus, the relative mobility μrel\mu_{\text{rel}} of joelons compared to electrons is:

μrel=qj/mjqe/me=3qe/7.88meqe/me=37.88\mu_{\text{rel}} = \frac{q_j / m_j}{q_e / m_e} = \frac{3q_e / 7.88m_e}{q_e / m_e} = \frac{3}{7.88}

μrel0.3807\mu_{\text{rel}} \approx 0.3807

So, the mobility of joelons is approximately 38.1% of the mobility of electrons.

2. Conductivity of Joelium Relative to an Ordinary Conductor

Conductivity (σ\sigma) is related to the number of charge carriers (nn), the charge (qq), and the mobility (μ\mu):

σ=nqμ\sigma = nq\mu

Assuming the number density nn of joelons and electrons is the same, the relative conductivity σrel\sigma_{\text{rel}} will be proportional to the product of the charge and mobility:

σrel=qjμjqeμe\sigma_{\text{rel}} = \frac{q_j \mu_j}{q_e \mu_e}

We know that qj=3qeq_j = 3q_e and μrel0.3807\mu_{\text{rel}} \approx 0.3807, so:

σrel=3qe×0.3807μeqe×μe=3×0.3807=1.1421\sigma_{\text{rel}} = \frac{3q_e \times 0.3807\mu_e}{q_e \times \mu_e} = 3 \times 0.3807 = 1.1421

Thus, the conductivity of joelium is approximately 1.1421 times that of an ordinary conductor.

Summary of Results:

  • Charge mobility of joelium: 0.38070.3807 times that of an ordinary conductor.
  • Conductivity of joelium: 1.14211.1421 times that of an ordinary conductor.

Let me know if you'd like more details, or if you have any questions!

Related Questions:

  1. How does temperature affect the mobility of charge carriers like joelons?
  2. What other factors might influence the conductivity of joelium aside from charge and mass?
  3. How does the drift velocity of joelons compare to that of electrons in a conductor?
  4. What implications could the higher conductivity of joelium have for practical applications?
  5. Can the number density of joelons be altered to further improve conductivity?

Tip:

Mobility is typically affected by factors like temperature and impurity scattering in the material, so improving these conditions can further enhance conductivity.

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Math Problem Analysis

Mathematical Concepts

Physics
Electric Conductivity
Charge Mobility
Proportions

Formulas

Charge mobility: μ = v_d / E
Mobility proportionality: μ ∝ q / m
Conductivity: σ = nqμ
Relative mobility: μ_rel = (q_j / m_j) / (q_e / m_e)
Relative conductivity: σ_rel = (q_j * μ_j) / (q_e * μ_e)

Theorems

Proportionality of charge mobility to charge and mass
Relationship between conductivity, charge, and mobility

Suitable Grade Level

Undergraduate Physics / Advanced High School