Math Problem Statement

solve

Laske puolijohteen varauksensiirtokonsentraatio, kun tiedetään johtavuus σ = 4.3 * 10^(-6) S/m, elektronien liikkuvuus μe = 9.0 m^2/(Vs) ja aukkojen liikkuvuus μh = 0.9 m^2/(Vs).

Solution

The problem in the image asks to calculate the charge carrier concentration nn in a semiconductor, given the electrical conductivity σ\sigma, electron mobility μe\mu_e, and hole mobility μh\mu_h. The relevant formula for conductivity in semiconductors is:

σ=qn(μe+μh)\sigma = q \cdot n \cdot (\mu_e + \mu_h)

Where:

  • σ\sigma is the conductivity,
  • qq is the elementary charge (q=1.6×1019Cq = 1.6 \times 10^{-19} \, \text{C}),
  • nn is the charge carrier concentration (what we are solving for),
  • μe\mu_e is the electron mobility,
  • μh\mu_h is the hole mobility.

We are given:

  • σ=4.3×106S/m\sigma = 4.3 \times 10^{-6} \, \text{S/m},
  • μe=9.0m2Vs\mu_e = 9.0 \, \frac{\text{m}^2}{\text{V} \cdot \text{s}},
  • μh=0.9m2Vs\mu_h = 0.9 \, \frac{\text{m}^2}{\text{V} \cdot \text{s}}.

Step 1: Rearrange the formula to solve for nn

n=σq(μe+μh)n = \frac{\sigma}{q \cdot (\mu_e + \mu_h)}

Step 2: Substitute the known values

n=4.3×106(1.6×1019)(9.0+0.9)n = \frac{4.3 \times 10^{-6}}{(1.6 \times 10^{-19}) \cdot (9.0 + 0.9)}

Step 3: Calculate

First, calculate the sum of mobilities:

μe+μh=9.0+0.9=9.9\mu_e + \mu_h = 9.0 + 0.9 = 9.9

Now, calculate the denominator:

q(μe+μh)=1.6×10199.9=1.584×1018q \cdot (\mu_e + \mu_h) = 1.6 \times 10^{-19} \cdot 9.9 = 1.584 \times 10^{-18}

Now calculate nn:

n=4.3×1061.584×1018=2.715×1012m3n = \frac{4.3 \times 10^{-6}}{1.584 \times 10^{-18}} = 2.715 \times 10^{12} \, \text{m}^{-3}

So, the charge carrier concentration is:

n=2.72×1012m3n = 2.72 \times 10^{12} \, \text{m}^{-3}

Would you like more details or have any questions?

Here are five related questions for further study:

  1. How does temperature affect electron and hole mobilities in semiconductors?
  2. What is the relationship between conductivity and charge carrier concentration in different types of semiconductors?
  3. How would the carrier concentration change if the mobility of holes were significantly higher?
  4. Can this equation be applied to intrinsic semiconductors, and how does it differ for extrinsic semiconductors?
  5. How does the concept of mobility vary between different types of materials like metals and semiconductors?

Tip: When dealing with semiconductor problems, keep in mind that both the mobility of electrons and holes contribute to conductivity, and their sum is key to calculating charge carrier concentration.

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Math Problem Analysis

Mathematical Concepts

Physics
Semiconductors
Electrical Conductivity
Charge Carrier Concentration

Formulas

σ = q * n * (μe + μh)
n = σ / (q * (μe + μh))

Theorems

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Suitable Grade Level

University level - Physics/Engineering