Math Problem Statement

Find \( \frac{dy}{dx} \), if \( y = 4u - 4 \) and \( u = -x^2 + 3 \).

Solution

To solve for dydx\frac{dy}{dx}, given that:

y=4u4andu=x2+3,y = 4u - 4 \quad \text{and} \quad u = -x^2 + 3,

we will follow these steps:

Step 1: Differentiate yy with respect to uu

From the equation y=4u4y = 4u - 4, differentiate yy with respect to uu: dydu=4.\frac{dy}{du} = 4.

Step 2: Differentiate uu with respect to xx

From the equation u=x2+3u = -x^2 + 3, differentiate uu with respect to xx: dudx=2x.\frac{du}{dx} = -2x.

Step 3: Apply the chain rule

Using the chain rule, dydx=dydududx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}, we get: dydx=4(2x)=8x.\frac{dy}{dx} = 4 \cdot (-2x) = -8x.

Thus, the final result is:

dydx=8x.\frac{dy}{dx} = -8x.

Let me know if you would like more details or have any questions!

Here are some related questions:

  1. How do you apply the chain rule in differentiation?
  2. What is implicit differentiation, and how does it differ from the chain rule?
  3. How do we differentiate polynomial functions?
  4. What is the significance of dudx\frac{du}{dx} in composite functions?
  5. Can the same approach be used to differentiate trigonometric functions?

Tip: Always identify the variables in your function and decide the appropriate rule of differentiation (e.g., chain rule, product rule) based on the relationships between them.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Chain Rule
Composite Functions

Formulas

Chain rule: \( \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} \)
Derivative of polynomial: \( \frac{d}{dx}(x^n) = nx^{n-1} \)

Theorems

Chain Rule

Suitable Grade Level

Grade 11-12 or early college