Math Problem Statement

In 2040, people all over the world were excited to discover Planet Z populated by friendly aliens. Scientists were working hard to make it technically possible to meet the new distant and long-awaited neighbors. This was difficult as many laws of nature on the planet appeared to be… “shifted“ compared to our blue planet. Additionally, most of the software/online problem solvers couldn’t help in preparations since they are tuned to our home planet environment. Even worse, people of 2040s rely on the computers completely and can do almost nothing “by hand” but now you're on board the spaceship #159881477, and the captain is asking to solve "ZP" (Z Planet) problem (you know what it means when captain is "asking"... that's an order):

Use the chain rule to find the derivative of f(x)=2e−8x6−3x7f(x)=2e-8x6-3x7

f'(x)=f′(x)=  

!!! The challenge is that the Chain Rule on Earth, f(g(x))'=f'(g)g'(x)f(g(x))′=f′(g)g′(x) ,  is "twisted" on Z planet as the following:

 f(g(x))'=f'(g)g'(x)f(g(x))′=f′(g)g′(x)    (all the other rules have not been changed).

Solution

Let's solve the problem step by step using the twisted Chain Rule on Z Planet.

We are tasked with finding the derivative of the function:

f(x)=2e8x63x7f(x) = 2e^{-8x^6} - 3x^7

Step 1: Differentiate the second part (no twist needed for power of xx).

We can break this function into two parts:

  1. 2e8x62e^{-8x^6}
  2. 3x7-3x^7

We first differentiate 3x7-3x^7, which is straightforward using the power rule:

ddx[3x7]=21x6\frac{d}{dx}[-3x^7] = -21x^6

Now, let's focus on the more challenging part involving the exponential.

Step 2: Differentiate the exponential part using the twisted Chain Rule.

The term we need to differentiate is 2e8x62e^{-8x^6}.

Apply the twisted chain rule:

On Z Planet, the Chain Rule works the same way as Earth, but we are cautious about the twists. The derivative of eg(x)e^{g(x)} is:

ddx[eg(x)]=eg(x)g(x)\frac{d}{dx}[e^{g(x)}] = e^{g(x)} \cdot g'(x)

Here, g(x)=8x6g(x) = -8x^6.

  1. Differentiate the exponent g(x)=8x6g(x) = -8x^6: g(x)=ddx[8x6]=48x5g'(x) = \frac{d}{dx}[-8x^6] = -48x^5

  2. Apply the chain rule (twisted rule, but it's functionally the same): ddx[2e8x6]=2e8x6(48x5)\frac{d}{dx}[2e^{-8x^6}] = 2e^{-8x^6} \cdot (-48x^5)

    Simplifying:

    =96x5e8x6= -96x^5 e^{-8x^6}

Step 3: Combine the results.

Now, we combine the derivatives of both terms:

f(x)=96x5e8x621x6f'(x) = -96x^5 e^{-8x^6} - 21x^6

Final Answer:

f(x)=96x5e8x621x6f'(x) = -96x^5 e^{-8x^6} - 21x^6

This is the derivative of the given function using the chain rule on Z Planet!

Would you like any further clarifications?

Here are some related questions:

  1. How does the chain rule differ on Z Planet from Earth in this context?
  2. What role does the power rule play in differentiating higher-order polynomials?
  3. How would the result change if the exponential involved other functions?
  4. How can the chain rule be applied to more complex nested functions?
  5. Why is it important to carefully apply

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Math Problem Analysis

Mathematical Concepts

Calculus
Differentiation
Chain Rule
Exponential Functions
Polynomial Differentiation

Formulas

Chain Rule: f(g(x))' = f'(g(x)) * g'(x)
Power Rule: d/dx[x^n] = nx^(n-1)
Exponential Derivative: d/dx[e^g(x)] = e^g(x) * g'(x)

Theorems

Chain Rule
Power Rule

Suitable Grade Level

Undergraduate Level Calculus