Math Problem Statement

If A = {1, 2, 3, 4, 5} and B = {2, 3, 6, 8} then find

a) Bx A

b) ΑΔ Β

Solution

Let's solve both parts step by step:

Given Sets:

  • A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\}
  • B={2,3,6,8}B = \{2, 3, 6, 8\}

a) B×AB \times A (Cartesian Product of BB and AA)

The Cartesian product B×AB \times A is the set of all ordered pairs (b,a)(b, a), where bBb \in B and aAa \in A.

So, we take every element from set BB and pair it with every element from set AA.

B×A={(2,1),(2,2),(2,3),(2,4),(2,5),(3,1),(3,2),(3,3),(3,4),(3,5),(6,1),(6,2),(6,3),(6,4),(6,5),(8,1),(8,2),(8,3),(8,4),(8,5)}B \times A = \{(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5)\}

b) AΔBA \Delta B (Symmetric Difference of AA and BB)

The symmetric difference AΔBA \Delta B is the set of elements that are in AA or BB but not in both. In other words, it is the union of ABA \setminus B and BAB \setminus A.

  • AB={1,4,5}A \setminus B = \{1, 4, 5\} (elements in AA but not in BB)
  • BA={6,8}B \setminus A = \{6, 8\} (elements in BB but not in AA)

So, AΔB={1,4,5,6,8}A \Delta B = \{1, 4, 5, 6, 8\}.

Final Answers:

a) B×A={(2,1),(2,2),(2,3),(2,4),(2,5),(3,1),(3,2),(3,3),(3,4),(3,5),(6,1),(6,2),(6,3),(6,4),(6,5),(8,1),(8,2),(8,3),(8,4),(8,5)}B \times A = \{(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5)\}

b) AΔB={1,4,5,6,8}A \Delta B = \{1, 4, 5, 6, 8\}


Would you like more details or have any questions on this?

Here are 5 related questions for further practice:

  1. Find the Cartesian product A×BA \times B.
  2. Determine (AB)(A \cap B), the intersection of sets AA and BB.
  3. Find ABA \cup B, the union of sets AA and BB.
  4. What is the complement of set AA if the universal set is U={1,2,3,4,5,6,7,8,9}U = \{1, 2, 3, 4, 5, 6, 7, 8, 9\}?
  5. Find the symmetric difference (AΔB)×B(A \Delta B) \times B.

Tip: The symmetric difference can be viewed as the set of elements that are "exclusive" to each set, meaning they belong to one set or the other, but not both.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Cartesian Product
Symmetric Difference

Formulas

Cartesian Product: B x A = {(b, a) | b ∈ B, a ∈ A}
Symmetric Difference: A Δ B = (A ∪ B) - (A ∩ B)

Theorems

Symmetric Difference Theorem
Cartesian Product Properties

Suitable Grade Level

Grades 8-10