Math Problem Statement
obtain the Cartesian equation of the plane that passes through the points (3, 5, 1), (2, 2, 2) and (−2, −2, 0).
Solution
To find the Cartesian equation of the plane passing through the points , , and , follow these steps:
Step 1: Find two direction vectors in the plane
Given points, we form two vectors that lie in the plane:
Step 2: Compute the normal vector
The normal vector to the plane, , is perpendicular to both and . Compute it using the cross product:
The determinant for the cross product is:
\mathbf{i} & \mathbf{j} & \mathbf{k} \\ -1 & -3 & 1 \\ -5 & -7 & -1 \end{vmatrix}$$ Expanding: $$\vec{n} = \mathbf{i} \begin{vmatrix} -3 & 1 \\ -7 & -1 \end{vmatrix} - \mathbf{j} \begin{vmatrix} -1 & 1 \\ -5 & -1 \end{vmatrix} + \mathbf{k} \begin{vmatrix} -1 & -3 \\ -5 & -7 \end{vmatrix}$$ Simplify the minors: $$\vec{n} = \mathbf{i}((-3)(-1) - (1)(-7)) - \mathbf{j}((-1)(-1) - (-5)(1)) + \mathbf{k}((-1)(-7) - (-3)(-5))$$ $$\vec{n} = \mathbf{i}(3 + 7) - \mathbf{j}(1 + 5) + \mathbf{k}(-7 - 15)$$ $$\vec{n} = 10\mathbf{i} - 6\mathbf{j} - 22\mathbf{k}$$ Thus, the normal vector is: $$\vec{n} = (10, -6, -22)$$ --- ### **Step 3: Form the Cartesian equation of the plane** The general equation of a plane is: $$10x - 6y - 22z = d$$ Substitute the coordinates of a point (e.g., $$(3, 5, 1)$$) into the equation to find $$d$$: $$10(3) - 6(5) - 22(1) = d$$ $$30 - 30 - 22 = d$$ $$d = -22$$ Thus, the equation of the plane is: $$10x - 6y - 22z = -22$$ --- ### **Final Answer** The Cartesian equation of the plane is: $$10x - 6y - 22z + 22 = 0$$ Would you like further explanation or assistance with any step? 😊 --- ### **Related Questions** 1. How do you compute the cross product of two vectors geometrically? 2. What does the normal vector of a plane represent in 3D space? 3. How can the distance from a point to a plane be calculated? 4. What are the parametric equations of the same plane? 5. How can you verify if a given point lies on a plane? --- ### **Tip** When computing the cross product, carefully organize the determinant's expansion to avoid sign errors.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Vector Algebra
Cartesian Geometry
Planes in 3D Space
Formulas
Direction vector formula: v = (x2 - x1, y2 - y1, z2 - z1)
Cross product formula for normal vector: n = v1 × v2
Cartesian equation of a plane: ax + by + cz = d
Theorems
Cross Product Theorem
Plane Equation Theorem
Suitable Grade Level
Grades 10-12
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