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The image shows a problem regarding the capacitance ratio of a varactor. The formula provided is:

\[
\text{Varactor Capacitance Ratio} = \text{Tuning Ratio} = CR = \frac{C_{\text{max}}}{C_{\text{min}}}
\]

The problem asks to find the capacitance ratio given that the capacitance of a certain varactor can vary from 15 pF to 100 pF.

### Step-by-step solution:

We are given:
- \( C_{\text{min}} = 15 \, \text{pF} \)
- \( C_{\text{max}} = 100 \, \text{pF} \)

Using the formula for the capacitance ratio:

\[
CR = \frac{C_{\text{max}}}{C_{\text{min}}} = \frac{100 \, \text{pF}}{15 \, \text{pF}} = \frac{100}{15} \approx 6.67
\]

### Answer:
The capacitance ratio is approximately **6.67**.

Let me know if you'd like any further details or clarification!

Here are 5 related questions:
1. What is the significance of the capacitance ratio in tuning circuits?
2. How does a varactor diode change its capacitance?
3. What is the typical application of varactor diodes in electronics?
4. How do different bias voltages affect the capacitance of a varactor?
5. Can the capacitance ratio be greater than the calculated value in practice?

**Tip:** Always double-check units when calculating capacitance ratios to avoid any errors.

A capacitance of a certain varactor can be varied from 15 pF to 100 pF. What is the capacitance ratio?

Learn how to calculate the capacitance ratio for a varactor diode where the capacitance varies from 15 pF to 100 pF. The solution involves using the formula CR = Cmax / Cmin. This detailed solution is suitable for students studying electronics at an advanced level.

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