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The new image contains a physics problem about capacitors and dielectric constants. The problem is related to the behavior of a capacitor when immersed in a non-conducting liquid and how the capacitance and other properties change with the concentration of the liquid.

Here is the analysis of the given options:

- **Option A:** The capacitance of the capacitor decreases.
- **Option B:** The electric field intensity between the plates of the capacitor increases.
- **Option C:** The voltage difference between the plates of the capacitor increases.
- **Option D:** The resistance of the solution decreases between \( M \) and \( N \).

### Analysis:
1. **Capacitance and Dielectric Constant:**
   - Capacitance (\( C \)) of a capacitor is given by \( C = \varepsilon_r \varepsilon_0 \frac{A}{d} \), where \( \varepsilon_r \) is the relative permittivity (dielectric constant), \( \varepsilon_0 \) is the vacuum permittivity, \( A \) is the area of the plates, and \( d \) is the distance between them.
   - The given graph shows that \( \varepsilon_r \) decreases with increasing concentration \( C_m \). Hence, the capacitance \( C \) decreases.

2. **Electric Field Intensity:**
   - The electric field \( E \) is given by \( E = \frac{V}{d} \), where \( V \) is the voltage and \( d \) is the distance between the plates.
   - If \( \varepsilon_r \) decreases and \( C \) decreases, the stored charge \( Q \) might decrease, affecting the electric field.

3. **Voltage Difference:**
   - The voltage \( V \) across the capacitor remains constant as it is connected to a constant voltage source.

4. **Resistance of the Solution:**
   - The resistance \( R \) between points \( M \) and \( N \) might be affected by the concentration of the solution. Typically, the resistance decreases with increased ion concentration.

### Correct Answer:
Given these points, the correct answer is:

**D. The resistance of the solution decreases between \( M \) and \( N \).**

Would you like more details or have any questions? Here are some related questions you might ask:

1. How does a dielectric material affect the capacitance of a capacitor?
2. What is the relationship between capacitance, voltage, and stored charge in a capacitor?
3. How does the electric field in a capacitor change with varying dielectric constant?
4. Can you explain the behavior of resistance in electrolyte solutions?
5. What are practical applications of capacitors with varying dielectric materials?

**Tip:** The dielectric constant (\( \varepsilon_r \)) significantly influences the capacitance of a capacitor. Higher dielectric constants increase capacitance, while lower ones decrease it.

Understand how the capacitance of a capacitor changes with varying dielectric constants in a physics problem. Explore the effects on electric field intensity and resistance in electrolyte solutions. Suitable for advanced high school students.

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