Math Problem Statement

A 0.300 M solution of LiOH that contains 0.500 mole of solute would have a volume, in milliliters, of

Solution

To find the volume of the solution in milliliters, we can use the relationship between molarity, moles of solute, and volume of solution. The formula is:

Molarity(M)=molesofsolutevolumeofsolution(inliters)Molarity (M) = \frac{moles \, of \, solute}{volume \, of \, solution \, (in \, liters)}

We are given:

  • Molarity M=0.300MM = 0.300 \, M
  • Moles of solute = 0.500 moles

We need to find the volume of the solution. Rearranging the formula to solve for volume:

volume(inliters)=molesofsoluteMolarityvolume \, (in \, liters) = \frac{moles \, of \, solute}{Molarity}

Substitute the known values:

volume(inliters)=0.500moles0.300M=1.667litersvolume \, (in \, liters) = \frac{0.500 \, moles}{0.300 \, M} = 1.667 \, liters

Since 1 liter = 1000 milliliters, we convert the volume into milliliters:

volume(inmilliliters)=1.667liters×1000=1667millilitersvolume \, (in \, milliliters) = 1.667 \, liters \times 1000 = 1667 \, milliliters

Therefore, the volume of the solution is 1667 milliliters.


Would you like a detailed explanation of any step or have further questions?

Here are some related questions:

  1. How would the volume change if the molarity were increased to 0.500 M?
  2. How do you calculate the molarity of a solution if you know the volume and moles of solute?
  3. What is the role of molarity in titrations?
  4. How can you calculate the molarity of a solution using dilution?
  5. How do you determine the amount of solute needed for a specific volume and molarity?

Tip: Remember that molarity is always moles of solute per liter of solution. Ensure that the volume is in liters before performing any calculations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Molarity
Unit Conversion
Volume Calculation

Formulas

Molarity (M) = moles of solute / volume of solution (in liters)
Volume (in liters) = moles of solute / Molarity
1 liter = 1000 milliliters

Theorems

-

Suitable Grade Level

Grades 9-11