Determine the number of moles of HCl in 129 mL of a 1.83 M solution of HCl.

To determine the number of moles of \( \text{HCl} \) in a solution, we can use the formula:

\[
\text{Moles of HCl} = \text{Molarity} \times \text{Volume (in liters)}
\]

### Given:
- **Molarity (M)** = 1.83 M
- **Volume** = 129 mL

First, convert the volume from milliliters to liters:

\[
129 \, \text{mL} = 0.129 \, \text{L}
\]

### Calculation:
Now, plug the values into the formula:

\[
\text{Moles of HCl} = 1.83 \, \text{M} \times 0.129 \, \text{L} = 0.23607 \, \text{moles}
\]

### Answer:
The number of moles of \( \text{HCl} \) in 129 mL of a 1.83 M solution is approximately:

\[
0.236 \, \text{moles}
\]

Would you like a more detailed explanation, or do you have any questions?

Here are some related questions:
1. How would you calculate the mass of HCl in this solution?
2. What is the molar mass of HCl, and how does it affect calculations?
3. How does the concentration (molarity) affect the amount of substance in a solution?
4. How can we determine the volume needed to reach a specific amount of moles?
5. What happens to the concentration if water is added to this solution?

**Tip:** Always ensure volumes are in liters when using molarity to calculate moles.

Determine the number of moles of HCl in 129 mL of a 1.83 M solution of HCl.

Learn how to calculate the number of moles of HCl in a solution with 1.83 M concentration and 129 mL volume. This solution involves molarity and unit conversion from milliliters to liters. Perfect for high school chemistry students.

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