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The problem asks for the total mass of cofactor A in a yeast colony containing \(10^5\) cells, given that the mass of cofactor A in one yeast cell is 33.8 picograms (pg). The answer must be provided in micrograms (µg).

Here’s how to solve it:

1. **Convert picograms to micrograms:**
   \(1 \, \text{pg} = 10^{-6} \, \mu\text{g}\).
   
   Therefore, the mass of cofactor A in one yeast cell in micrograms is:
   \[
   33.8 \, \text{pg} = 33.8 \times 10^{-6} \, \mu\text{g}.
   \]

2. **Find the total mass in the colony:**
   The colony contains \(10^5\) cells, so the total mass in the colony is:
   \[
   \text{Total mass} = \left(33.8 \times 10^{-6} \, \mu\text{g}\right) \times 10^5.
   \]

3. **Perform the calculation:**
   \[
   \text{Total mass} = 33.8 \times 10^{-6} \times 10^5 = 33.8 \times 10^{-1} = 3.38 \, \mu\text{g}.
   \]

So, the total mass of cofactor A in the yeast colony is **3.38 µg**.

Would you like more details or have any questions?

Here are 5 related questions to deepen your understanding:
1. How do you convert picograms to nanograms or milligrams?
2. What are other common conversions between units of mass?
3. How would the result change if the colony had \(10^6\) cells instead of \(10^5\)?
4. Can you describe other biological measurements that require similar unit conversions?
5. What are the advantages of using standard scientific notation for small measurements like picograms?

**Tip:** When converting between units, always pay attention to powers of ten, especially when dealing with very small or very large numbers.

A molecular biologist measures the mass of cofactor A in an average yeast cell. The mass is 33.8 pg. What is the total mass in micrograms of cofactor A in a yeast colony containing 10^5 cells? Write your answer as a decimal.

This problem involves converting the mass of cofactor A in yeast cells from picograms to micrograms and calculating the total mass in a colony of 10^5 cells. The step-by-step solution demonstrates scientific notation and unit conversion.

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