Math Problem Statement
In a conventional activated sludge treatment plant, the mixed liquor suspended solids were 2,800 mg/L. If the aeration basin is 140 feet long by 50 feet wide by 12 feet deep, how many pounds of solids are under aeration?
Solution
To calculate the pounds of solids under aeration in the aeration basin, we need to follow these steps:
1. Calculate the volume of the aeration basin:
The dimensions of the aeration basin are given as:
- Length = 140 feet
- Width = 50 feet
- Depth = 12 feet
The volume of the aeration basin can be calculated by multiplying the length, width, and depth:
2. Convert volume from cubic feet to gallons:
Since 1 cubic foot = 7.48 gallons, we can convert the volume:
3. Calculate the total pounds of solids:
We know the concentration of the mixed liquor suspended solids (MLSS) is 2,800 mg/L. To convert this into pounds per gallon:
- 1 mg/L = 1 part per million (ppm) = 1 milligram per liter (mg/L)
- 1 mg = kg
- 1 liter = 1 kg of water = 1 gallon of water weighs approximately 8.34 pounds
Thus, 2,800 mg/L can be converted to pounds per gallon as:
4. Calculate total solids in pounds:
Finally, multiply the volume in gallons by the concentration in pounds per gallon:
Final Answer:
The total pounds of solids under aeration is approximately 14,712 pounds.
Would you like further details on any of these steps or have additional questions?
Related questions:
- How would the solids concentration change if the depth of the aeration basin were increased?
- How does the volume of the aeration basin affect the efficiency of the treatment process?
- What is the significance of mixed liquor suspended solids (MLSS) in wastewater treatment?
- How can you adjust the aeration basin size to meet a specific MLSS requirement?
- What are common methods for measuring and controlling MLSS in activated sludge systems?
Tip:
Ensure to regularly monitor the MLSS concentration to avoid overloading the system and maintain effective biological treatment.
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Math Problem Analysis
Mathematical Concepts
Volume Calculation
Unit Conversion
Solids Concentration
Formulas
Volume = Length × Width × Depth
1 cubic foot = 7.48 gallons
Solids Concentration (lb/gal) = mg/L × (1 lb / 1,000,000 mg) × 8.34 lb/gal
Total Solids = Volume in gallons × Solids Concentration (lb/gal)
Theorems
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Suitable Grade Level
Grades 11-12
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