Math Problem Statement

A 40-foot-diameter gravity thickener is used to thicken 80 gallons per minute of primary sludge. The primary sludge is applied to the thickener at an initial sludge solids concentration of 4 percent. Find the solids loading rate applied to the gravity thickener in pounds per square foot per day. Round to the nearest whole number.

Solution

To find the solids loading rate applied to the gravity thickener in pounds per square foot per day, we can break the problem down into the following steps:

Step 1: Convert the flow rate to gallons per day

We are given the flow rate of 80 gallons per minute. To convert this to gallons per day:

80gallons per minute×60minutes per hour×24hours per day=115,200gallons per day80 \, \text{gallons per minute} \times 60 \, \text{minutes per hour} \times 24 \, \text{hours per day} = 115,200 \, \text{gallons per day}

Step 2: Convert the concentration to a decimal

The concentration of solids in the sludge is given as 4%. To work with this, we need to convert it to decimal form:

4%=4100=0.044\% = \frac{4}{100} = 0.04

Step 3: Calculate the amount of solids in pounds

The amount of solids in the sludge is 4% of the total flow rate. First, we need to convert the gallons of sludge to pounds of sludge. The weight of water is approximately 8.34 pounds per gallon. Thus, the total pounds of sludge per day is:

115,200gallons per day×0.04(concentration of solids)×8.34pounds per gallon=38,438.4pounds of solids per day115,200 \, \text{gallons per day} \times 0.04 \, \text{(concentration of solids)} \times 8.34 \, \text{pounds per gallon} = 38,438.4 \, \text{pounds of solids per day}

Step 4: Calculate the surface area of the thickener

The thickener has a diameter of 40 feet, so its radius is:

402=20feet\frac{40}{2} = 20 \, \text{feet}

The surface area AA of the thickener is the area of a circle, which can be calculated using the formula:

A=πr2=π(20)2=1,256.64square feetA = \pi r^2 = \pi (20)^2 = 1,256.64 \, \text{square feet}

Step 5: Calculate the solids loading rate

Now, we can calculate the solids loading rate by dividing the total pounds of solids by the surface area of the thickener:

Solids loading rate=38,438.4pounds per day1,256.64square feet=30.6pounds per square foot per day\text{Solids loading rate} = \frac{38,438.4 \, \text{pounds per day}}{1,256.64 \, \text{square feet}} = 30.6 \, \text{pounds per square foot per day}

Final Answer:

The solids loading rate applied to the gravity thickener is approximately 31 pounds per square foot per day (rounded to the nearest whole number).


Would you like any additional clarification on the steps involved?

Here are 5 related questions to expand on this topic:

  1. How does the initial sludge concentration affect the solids loading rate?
  2. What would happen if the diameter of the thickener was reduced to 30 feet?
  3. How would increasing the sludge flow rate affect the performance of the thickener?
  4. What role does gravity play in the thickening process?
  5. How can the efficiency of a gravity thickener be improved?

Tip: Always ensure that units are consistent throughout your calculations to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Unit Conversion
Surface Area Calculation
Solids Loading Rate
Basic Algebra

Formulas

Flow Rate (gallons per day) = Flow Rate (gallons per minute) × 60 × 24
Amount of Solids (pounds per day) = Flow Rate (gallons per day) × Concentration × Weight of Water (8.34 pounds per gallon)
Surface Area (square feet) = π × (radius)^2
Solids Loading Rate (pounds per square foot per day) = Total Solids (pounds per day) / Surface Area (square feet)

Theorems

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Suitable Grade Level

College Level (Environmental Engineering, Wastewater Treatment)