Suppose log(a) = - 8; log(b) = 5 Find log ab . log(ab) =

To find \(\log(ab)\) given \(\log(a) = -8\) and \(\log(b) = 5\), we use the property of logarithms that states:

\[ \log(ab) = \log(a) + \log(b) \]

Now, substitute the given values:

\[ \log(ab) = \log(a) + \log(b) = -8 + 5 \]

So,

\[ \log(ab) = -3 \]

Therefore, \(\log(ab) = -3\).

If you need any more details or have any questions, please let me know.

Here are some related questions:

1. If \(\log(a) = 2\) and \(\log(b) = 3\), what is \(\log(ab)\)?
2. How can you find \(\log(a/b)\) given \(\log(a)\) and \(\log(b)\)?
3. If \(\log(a) = -8\), what is \(\log(a^2)\)?
4. How do you simplify \(\log(ab^2)\)?
5. Given \(\log(a) = -8\), how do you find the value of \(a\)?
6.

Learn how to calculate \( \log(ab) \) given \( \log(a) = -8 \) and \( \log(b) = 5 \). Follow a detailed step-by-step solution using logarithmic properties. Suitable for high school students.

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