Question 14:
"Dalam suatu reuni dihadiri oleh 8 orang. Jika mereka berjabat tangan masing-masing satu kali, maka banyak jabat tangan pada reuni tersebut adalah ...."

This problem is asking for the number of handshakes at a gathering where 8 people attend, and each pair of people shakes hands exactly once.

Solution:

The formula to determine the number of unique handshakes in a group of $n$ people is:

$\text{Handshakes} = \frac{n(n - 1)}{2}$

Where $n$ is the number of people. For this case, $n = 8$:

[ \text{Handshakes} = \frac{8(8 - 1)}{2} = \frac{8 \times 7}{2} = \frac