Given the function $f(x) = (1.3)^x$, let's calculate $f(0)$.

We substitute $x = 0$ into the function:

$f(0) = (1.3)^0$

Using the property of exponents that any non-zero number raised to the power of 0 is 1:

$f(0) = 1$

So, $f(0) = 1$.

Let me know if you'd like more details or have any questions!

Here are 5 related questions:

1. What is the value of $f(1)$ for $f(x) = (1.3)^x$?
2. How does the value of $f(x) = (1.3)^x$ change as $x$ increases?
3. What is the value of $f(-1)$ for the function $f(x) = (1.3)^x$?
4. What happens to $f(x) = (1.3)^x$ as $x$ approaches infinity?
5. How would the graph of $f(x) = (1.3)^x$ compare to that of $f(x) = (2)^x$?

Tip: Exponential functions like $f(x) = a^x$ grow faster as the base $a$ increases, especially when $x$ is positive.