R1 = 120Ω dan R2 = 1,5 MΩ .
R1 = 1,5 kΩ dan R2 = 120 Ω .
R1 = 1,5 MΩ dan R2 = 1,5 kΩ .

It seems like you've provided values for resistances, \( R_1 \) and \( R_2 \), in three different configurations. Let's summarize them for clarity:

1. **First Configuration:**
   - \( R_1 = 120 \, \Omega \)
   - \( R_2 = 1.5 \, \text{M}\Omega \)

2. **Second Configuration:**
   - \( R_1 = 1.5 \, \text{k}\Omega \)
   - \( R_2 = 120 \, \Omega \)

3. **Third Configuration:**
   - \( R_1 = 1.5 \, \text{M}\Omega \)
   - \( R_2 = 1.5 \, \text{k}\Omega \)

Would you like to calculate the equivalent resistance in series or parallel for these configurations, or analyze them in another way?

Please let me know if you want details, and here are five possible follow-up questions to explore:

1. How do we calculate equivalent resistance in series for each configuration?
2. What is the formula for calculating equivalent resistance in parallel?
3. How do different resistor values affect current in a circuit?
4. What are the implications of having resistors with such varying magnitudes?
5. Could we use these values in a voltage divider circuit? If so, how would we set it up?

**Tip:** For circuits, remember that resistors in series add directly, while resistors in parallel combine inversely, affecting overall resistance differently.

R1 = 120Ω dan R2 = 1,5 MΩ . R1 = 1,5 kΩ dan R2 = 120 Ω . R1 = 1,5 MΩ dan R2 = 1,5 kΩ .

Explore how to calculate equivalent resistance in different configurations of resistors R1 and R2, including 120Ω, 1.5MΩ, and 1.5kΩ values. This problem covers series and parallel circuits and applies Ohm's Law for accurate calculations, ideal for Grades 10-12.

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