Math Problem Statement

Work out the shortest distance between planet Q and planet R. Given the distances: Planet Q is 3.6 x 10^6 km from planet P, and Planet R is 1.6 x 10^7 km from planet P.

Solution

The problem involves finding the shortest distance between two planets, QQ and RR, using the given distances:

  • The distance from Planet QQ to Planet PP is 3.6×1063.6 \times 10^6 km.
  • The distance from Planet RR to Planet PP is 1.6×1071.6 \times 10^7 km.

From the diagram, it appears that the triangle formed by the three planets is a right-angled triangle, where:

  • The distance between PP and QQ is one leg of the triangle.
  • The distance between PP and RR is the other leg of the triangle.

We can use the Pythagorean theorem to find the shortest distance (the hypotenuse) between Planet QQ and Planet RR. The formula for the Pythagorean theorem is:

c=a2+b2c = \sqrt{a^2 + b^2}

Where:

  • a=3.6×106a = 3.6 \times 10^6 km (distance between QQ and PP),
  • b=1.6×107b = 1.6 \times 10^7 km (distance between RR and PP).

Let's calculate that now.The shortest distance between Planet QQ and Planet RR is 1.64×1071.64 \times 10^7 km, in standard form.

Would you like more details or have any questions? Here are some related questions to further expand your understanding:

  1. How is the Pythagorean theorem applied to different geometrical shapes?
  2. What are the real-world applications of the Pythagorean theorem in astronomy?
  3. How do you convert between standard form and scientific notation?
  4. What other methods can be used to calculate distances in space?
  5. How would rounding affect the precision of distances in scientific contexts?

Tip: In problems involving large distances like those in space, using scientific notation helps simplify calculations and avoid errors in handling very large numbers.

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Math Problem Analysis

Mathematical Concepts

Geometry
Scientific Notation
Pythagorean Theorem

Formulas

c = sqrt(a^2 + b^2)

Theorems

Pythagorean theorem

Suitable Grade Level

High School