Math Problem Statement

Sebuah pabrik rokok 'Sampurna' menghasilkan 1.000.000 bungkus rokok pada tahun pertama, dan 1.750.000 bungkus pada tahun ke-6. a. Andaikan produksinya konstan, berapa tambahan produksinya per tahun? b. Berapa besar produksi rokoknya pada tahun ke-11?

Solution

The problem provided discusses the production of cigarettes by a factory. Let's break down and solve it step by step.

Given Data:

  1. Initial production in year 1: 1,000,000 packs.
  2. Production in year 6: 1,750,000 packs.

We assume the production increases at a constant rate each year.

a. Find the additional production per year:

The increase in production from year 1 to year 6 is linear, meaning the same amount is added every year. To find the annual increase, we can use the formula for the slope between two points in arithmetic sequences:

Increase per year=Production in year 6Production in year 161\text{Increase per year} = \frac{\text{Production in year 6} - \text{Production in year 1}}{6 - 1}

Let's calculate this.

Increase per year=1,750,0001,000,00061=750,0005=150,000\text{Increase per year} = \frac{1,750,000 - 1,000,000}{6 - 1} = \frac{750,000}{5} = 150,000

So, the production increases by 150,000 packs per year.

b. Find the production in year 11:

Since the production increases by 150,000 packs per year, we can calculate the production in year 11 by extending the arithmetic sequence.

The formula for the nn-th term of an arithmetic sequence is:

Pn=P1+(n1)×dP_n = P_1 + (n - 1) \times d

Where:

  • PnP_n is the production in year nn,
  • P1P_1 is the production in year 1 (1,000,000 packs),
  • dd is the increase per year (150,000),
  • n=11n = 11.

Substituting the values:

P11=1,000,000+(111)×150,000P_{11} = 1,000,000 + (11 - 1) \times 150,000 P11=1,000,000+10×150,000P_{11} = 1,000,000 + 10 \times 150,000 P11=1,000,000+1,500,000=2,500,000P_{11} = 1,000,000 + 1,500,000 = 2,500,000

Thus, the production in year 11 will be 2,500,000 packs.

Summary:

  • The additional production per year is 150,000 packs.
  • The production in year 11 will be 2,500,000 packs.

Would you like more details on any step or further clarification? Here are some related questions for you:

  1. What if the production increased by a different amount every year instead of a constant rate?
  2. How would we calculate the production in year 20?
  3. Can we model this problem using a different method like geometric sequences?
  4. What if the production in year 1 had been lower—how would that change the result?
  5. Can this method apply to other real-world problems, such as factory output for different products?

Tip: Always verify if the given pattern (constant increase) holds in similar real-world scenarios before making predictions.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Arithmetic Progression
Linear Growth

Formulas

Increase per year = (Production in year 6 - Production in year 1) / (6 - 1)
Pn = P1 + (n - 1) * d

Theorems

Arithmetic Progression Formula

Suitable Grade Level

Grades 9-10