Math Problem Statement

To solve each problem, use the appropriate formulas, show the given used, conversions and solutions. Highlight the final answer and put the correct Sl units.

  1. Calculate the work done by a person weighing 115 lbs carrying goods 50 degrees on his back and exerts 450N of force travelling at 110 feet of distance.

Solution

Problem Statement:

We are tasked with calculating the work done by a person who exerts 450 N of force while carrying goods at a 50° angle and traveling a distance of 110 feet. The person weighs 115 lbs. However, the person's weight is not needed to solve the problem, as the focus is on the force exerted and the distance traveled.

Formula for Work:

The work WW done by a force is calculated by the formula:

W=Fdcos(θ)W = F \cdot d \cdot \cos(\theta)

Where:

  • WW is the work done (in joules),
  • FF is the force applied (in newtons),
  • dd is the distance traveled (in meters),
  • θ\theta is the angle between the force and the direction of motion (in degrees).

Given:

  • Force applied F=450NF = 450 \, \text{N},
  • Distance traveled d=110feetd = 110 \, \text{feet},
  • Angle θ=50\theta = 50^\circ.

Step 1: Conversion of distance to meters:

We need to convert the distance from feet to meters. The conversion factor is:

1foot=0.3048meters1 \, \text{foot} = 0.3048 \, \text{meters}

So,

d=110feet×0.3048metersfoot=33.528metersd = 110 \, \text{feet} \times 0.3048 \, \frac{\text{meters}}{\text{foot}} = 33.528 \, \text{meters}

Step 2: Calculate the work done:

Now that we have the distance in meters, we can substitute the values into the work formula:

W=450N×33.528m×cos(50)W = 450 \, \text{N} \times 33.528 \, \text{m} \times \cos(50^\circ)

We'll calculate the cosine of 5050^\circ and then the work:

cos(50)0.6428\cos(50^\circ) \approx 0.6428

Now,

W=450N×33.528m×0.6428W = 450 \, \text{N} \times 33.528 \, \text{m} \times 0.6428

W450×33.528×0.6428W \approx 450 \times 33.528 \times 0.6428

W9674.36JoulesW \approx 9674.36 \, \text{Joules}

Final Answer:

The work done by the person is approximately:

9674.36Joules(J)\boxed{9674.36 \, \text{Joules} \, (\text{J})}

This is the amount of work done in moving the goods under the specified conditions.


Do you need further details or clarifications? Here are 5 follow-up questions:

  1. How does the angle of force affect the work done?
  2. How would the work change if the angle increased or decreased?
  3. What is the importance of converting units to SI units in physics problems?
  4. How does force differ from work in physical terms?
  5. What would happen if the person applied the force vertically instead of at an angle?

Tip: Always ensure that all units are converted to the correct SI units before performing calculations in physics.

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Math Problem Analysis

Mathematical Concepts

Physics
Work-Energy Theorem
Trigonometry
Unit Conversion

Formulas

W = F * d * cos(θ)
1 foot = 0.3048 meters
cos(50°) ≈ 0.6428

Theorems

Work-Energy Theorem

Suitable Grade Level

Grades 10-12