Calculate the work done by a person weighing 115 lbs carrying goods 50 degrees on his back and
exerts 450N of force travelling at 110 feet of distance.

To calculate the work done, we use the formula for work:

\[
W = F \cdot d \cdot \cos(\theta)
\]

Where:
- \( W \) = work done (in Joules)
- \( F \) = force exerted (in Newtons)
- \( d \) = distance traveled (in meters)
- \( \theta \) = angle of force applied relative to the direction of motion (in degrees)
- \( \cos(\theta) \) accounts for the component of force in the direction of motion

### Given:
- Force \( F = 450 \, \text{N} \)
- Distance \( d = 110 \, \text{feet} \) (Convert to meters: \( 1 \, \text{foot} = 0.3048 \, \text{m} \), so \( 110 \, \text{feet} = 110 \times 0.3048 = 33.528 \, \text{m} \))
- Angle \( \theta = 50^\circ \)

Now, let's calculate the work done:

\[
W = 450 \, \text{N} \times 33.528 \, \text{m} \times \cos(50^\circ)
\]

I'll now compute the value of \( W \).The work done by the person is approximately 9698.12 Joules.

Do you need more details or have any questions? 

Here are some related questions for further exploration:
1. How does the angle affect the amount of work done?
2. What happens if the force is applied perpendicular to the direction of motion?
3. How would the work done change if the person traveled twice the distance?
4. Can you calculate the work done if the force exerted changes with distance?
5. How does the weight of the person affect the calculation of work?

**Tip:** Always ensure that the force applied is in the same direction as the movement for maximum work efficiency.

Calculate the work done by a person weighing 115 lbs carrying goods 50 degrees on his back and exerts 450N of force travelling at 110 feet of distance.

This guide explains how to calculate the work done by a person exerting 450N of force over a distance of 110 feet at an angle of 50 degrees. Learn how to use the work formula, apply trigonometry, and perform unit conversions. Suitable for high school physics students in Grades 10-12.

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