Math Problem Statement

2 by 3 of a bottle was filled 1 by 2 l of water how many l of water will the bottle hold reciprocal method

Solution

To solve this problem using the reciprocal method, we will follow these steps:

  1. Understand the given quantities and relationships.
  2. Use the reciprocal to find the total capacity.

Given:

  • 23\frac{2}{3} of the bottle is filled with 12\frac{1}{2} liters of water.

We need to find the total capacity of the bottle.

Step-by-Step Solution

  1. Determine the amount filled:

    23\frac{2}{3} of the bottle holds 12\frac{1}{2} liters.

  2. Set up the equation:

    Let CC be the total capacity of the bottle in liters.

    23C=12\frac{2}{3}C = \frac{1}{2}

  3. Solve for CC using the reciprocal:

    To isolate CC, multiply both sides of the equation by the reciprocal of 23\frac{2}{3}.

    The reciprocal of 23\frac{2}{3} is 32\frac{3}{2}.

    Multiply both sides by 32\frac{3}{2}:

    C=12×32C = \frac{1}{2} \times \frac{3}{2}

  4. Perform the multiplication:

    C=1×32×2=34C = \frac{1 \times 3}{2 \times 2} = \frac{3}{4}

So, the total capacity of the bottle is 34\frac{3}{4} liters.

Conclusion

The bottle can hold 34\frac{3}{4} liters of water.

Would you like further details or have any questions?

Here are some related questions you might find helpful:

  1. How do you calculate the reciprocal of a fraction?
  2. What are other methods to find the total capacity of a container?
  3. How can you convert between different units of volume?
  4. How do you solve equations involving fractions?
  5. What is the importance of understanding ratios and proportions?
  6. How can you apply the concept of reciprocals in real-life situations?
  7. How do you verify the solution to a problem involving reciprocals?
  8. What are common mistakes to avoid when working with reciprocals?

Tip: When solving problems involving fractions, always double-check your calculations to ensure accuracy, especially when dealing with reciprocals and multiplication.

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Math Problem Analysis

Mathematical Concepts

Fractions
Reciprocal method

Formulas

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Theorems

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Suitable Grade Level

Grades 5-6