Math Problem Statement

Baity akhirnya memilih untuk menyewa rumah yang jaraknya masing-masing 24 km dan 55 km daripada sekolah dan stadium. Jika setiap pagi Baity memandu keretanya dengan laju seragam 80 km/h, hitung tempoh masa, dalam minit, yang diambil untuk beliau tiba di sekolah. Baity ingin menonton perlawanan bola sepak di Stadium dan sepak mula perlawanan tersebut adalah pada pukul 9:25 pagi. Beliau telah bertolak dari rumahnya pada 8:25 pagi dengan memandu dengan laju purata 110 km/h. Tentukan masa ini dan hitung sama ada Baity berjaya tiba di Stadium sebelum sepak mula itu. Berikan justifikasi anda.

Solution

Let's break down the question into parts and solve each one.

Part (b)(i):

Baity drives her car at a constant speed of 80km/h80 \, \text{km/h}. The distances to be covered are:

  • School: 24km24 \, \text{km}
  • Stadium: 55km55 \, \text{km}

We use the formula for time: Time (hours)=Distance (km)Speed (km/h)\text{Time (hours)} = \frac{\text{Distance (km)}}{\text{Speed (km/h)}}

  1. Time to the school: Time=2480=0.3hours\text{Time} = \frac{24}{80} = 0.3 \, \text{hours} Convert to minutes: 0.3×60=18minutes0.3 \times 60 = 18 \, \text{minutes}

  2. Time to the stadium: Time=5580=0.6875hours\text{Time} = \frac{55}{80} = 0.6875 \, \text{hours} Convert to minutes: 0.6875×60=41.25minutes(approximately 41 minutes 15 seconds).0.6875 \times 60 = 41.25 \, \text{minutes} \, \text{(approximately 41 minutes 15 seconds)}.

Answer for Part (i):

  • Time to the school: 18 minutes
  • Time to the stadium: 41 minutes 15 seconds

Part (b)(ii):

Baity needs to reach the stadium for a football match starting at 9:25 am, and the journey to the stadium is 55km55 \, \text{km} at 110km/h110 \, \text{km/h}.

  1. Calculate the time taken to reach the stadium: Time (hours)=Distance (km)Speed (km/h)=55110=0.5hours\text{Time (hours)} = \frac{\text{Distance (km)}}{\text{Speed (km/h)}} = \frac{55}{110} = 0.5 \, \text{hours} Convert to minutes: 0.5×60=30minutes.0.5 \times 60 = 30 \, \text{minutes}.

  2. To arrive on time, Baity must be at the stadium by 9:25 am. Subtracting the 30 minutes travel time, she must leave her house at: 9:25am30minutes=8:55am.9:25 \, \text{am} - 30 \, \text{minutes} = 8:55 \, \text{am}.

Answer for Part (ii): Baity must leave her house at 8:55 am to reach the stadium on time.


Summary of Answers:

  1. Part (i):

    • Time to school: 18 minutes
    • Time to stadium: 41 minutes 15 seconds
  2. Part (ii):

    • Baity must leave at 8:55 am to arrive at the stadium before the kick-off.

Would you like a detailed explanation for any specific part? Here are some related questions for further practice:

  1. What is the total travel time if Baity visits both the school and the stadium on the same day?
  2. If Baity's car slows down to 60km/h60 \, \text{km/h}, how would her travel times change?
  3. How far does Baity travel in total if she drives from her home to the school and then to the stadium?
  4. Calculate the average speed if Baity takes 1hour1 \, \text{hour} for a round trip to the school and stadium.
  5. If Baity starts 5 minutes late, what would her new departure time be to still reach the stadium on time?

Tip: Always check units (hours vs. minutes) carefully when solving speed, distance, and time problems.

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Math Problem Analysis

Mathematical Concepts

Speed, Distance, and Time
Conversion between hours and minutes

Formulas

Time = Distance / Speed
Conversion: Hours to Minutes (1 hour = 60 minutes)

Theorems

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Suitable Grade Level

Grades 6-8