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The question in the image describes a situation where the temperature at 3500 meters above sea level is -8°C, and the temperature increases by 1°C for every 100 meters you descend. The task is to find the temperature at 400 meters above sea level.

### Given:
- At 3500 meters: Temperature = -8°C
- For every 100 meters down, the temperature increases by 1°C.

### Steps to solve:

1. The difference in altitude between 3500 meters and 400 meters is:
   \[
   \Delta h = 3500 - 400 = 3100 \text{ meters}
   \]
   
2. For every 100 meters descended, the temperature increases by 1°C. So, for 3100 meters:
   \[
   \text{Temperature increase} = \frac{3100}{100} = 31^\circ C
   \]

3. Adding this temperature increase to the initial temperature at 3500 meters (-8°C):
   \[
   T(400 \text{ meters}) = -8 + 31 = 23^\circ C
   \]

Therefore, the temperature at 400 meters above sea level is **23°C**.

### Would you like more details or have any questions?

Here are 5 related questions you might consider:
1. What would the temperature be at 100 meters above sea level?
2. If the temperature increases by 2°C per 100 meters, how would that affect the result?
3. How would the temperature change if you ascended to 4000 meters?
4. What is the relationship between temperature and altitude in this case?
5. How could you apply this temperature-altitude relationship in different regions?

### Tip: 
Always ensure you carefully track units and changes in altitude when solving these types of problems!

Di suatu daerah yang berada pada ketinggian 3500 meter di atas permukaan laut suhunya -8°C. Jika setiap naik 100 meter suhu bertambah 1°C, maka suhu di ketinggian 400 meter di atas permukaan laut saat itu adalah?

Solve the problem of finding the temperature at 400 meters above sea level, given a rate of temperature increase of 1°C per 100 meters descent. Learn how linear relationships apply in this real-world example with clear step-by-step calculations. Suitable for Grades 5-7.

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