Math Problem Statement
Solution
To solve the surface area of the triangular prism shown in the image, we need to find the area of all the faces in the net and then sum them up.
The net consists of:
- Two triangular faces
- Three rectangular faces
Step 1: Area of the triangular faces
The triangles are right-angled, and their dimensions are given as:
- Base = 10 meters
- Height = 12 meters
The area of one triangle is: Since there are two triangular faces:
Step 2: Area of the rectangular faces
There are three rectangles with the following dimensions:
- One rectangle with length 20 meters and width (equal to the height of the triangle) 12 meters:
- One rectangle with length 21 meters and width (equal to the hypotenuse of the triangle, calculated using Pythagoras theorem):
- One rectangle with length 13 meters and width 20 meters:
Step 3: Total surface area
Now, summing up all the areas:
Thus, the surface area of the prism is 948.02 square meters.
Would you like further details or clarifications?
Here are 5 related questions you might find useful:
- How is the surface area of other types of prisms calculated?
- How does Pythagoras' theorem help in finding the hypotenuse?
- What is the difference between volume and surface area in 3D shapes?
- How do the dimensions of the net relate to the 3D shape itself?
- Can you explain how to find the area of complex polygons?
Tip: Always ensure the units used in your calculations are consistent, especially when dealing with different types of geometric shapes.
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Math Problem Analysis
Mathematical Concepts
Geometry
Surface Area
Nets of 3D Shapes
Right-Angled Triangles
Formulas
Area of a triangle = 1/2 × base × height
Surface Area of a prism = Sum of the areas of all faces
Hypotenuse = √(base^2 + height^2)
Theorems
Pythagoras' Theorem
Suitable Grade Level
Grades 8-10
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