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For F1 = 50 N, what is the support force at A in the x-direction? Give your answer in units of N.

To find the support force at point \( A \) in the x-direction, we can apply the principles of static equilibrium, specifically the sum of forces and moments being zero.

### Given Information:
- Force \( F_1 = 50 \, \text{N} \) acting horizontally to the right at the top-right point of the truss.
- There is also a vertical reaction force at the middle joint pointing downwards (typically representing load forces).

The support at \( A \) is a pin support, meaning it can resist forces in both the x and y directions. 

### Step-by-step Approach:

1. **Sum of Forces in the x-direction**:
   The truss is in equilibrium, so the sum of forces in the horizontal direction must equal zero:
   \[
   \Sigma F_x = 0
   \]
   Let \( A_x \) be the support reaction at \( A \) in the x-direction. The only other force in the horizontal direction is \( F_1 \), acting to the right. Thus:
   \[
   A_x + F_1 = 0
   \]
   Substituting \( F_1 = 50 \, \text{N} \):
   \[
   A_x + 50 = 0
   \]
   Solving for \( A_x \):
   \[
   A_x = -50 \, \text{N}
   \]
   The negative sign indicates that the reaction force at \( A \) is directed to the left.

### Final Answer:
The support force at \( A \) in the x-direction is \( A_x = -50 \, \text{N} \), meaning it acts to the left.

Would you like details on other forces or further explanations?

Here are 5 relative questions to expand:
1. What are the forces in the y-direction at support \( A \)?
2. How do the moments about point \( A \) affect the system?
3. How does the 4 m vertical distance impact the force distribution?
4. What would happen to the support reactions if \( F_1 \) increased to 100 N?
5. How can the internal forces in the truss members be calculated?

**Tip:** When solving trusses, remember that reactions at supports must balance all external forces to ensure equilibrium.

Learn how to find the support force at point A in the x-direction for a truss structure with an external force F1 = 50 N acting horizontally. The solution covers the principles of static equilibrium, including the sum of forces in the x-direction. Suitable for students in Grades 11-12.

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