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The problem is asking to find the area of the shaded region in the figure. The figure involves a quadrilateral \( ABCD \) with various segments and specific dimensions.

Given dimensions:

- \( MC = 2 \, \text{m} \)
- \( MN = 3 \, \text{m} \)
- \( ND = 4 \, \text{m} \)
- \( AD = 11 \, \text{m} \)
- \( BC = 9 \, \text{m} \)

### Plan:
1. **Identify the figure's geometry**:
   The figure appears to be a trapezoid-like shape where we have sufficient dimensions for base and height calculation.
   
2. **Divide the figure**:
   You can split the figure into smaller triangles or trapezoidal sections for area calculation.
   
3. **Calculate areas**:
   Use the areas of triangles and trapezoids to compute the total shaded area.

Let me proceed to compute the necessary values.The area of the shaded region in the figure is \( 90 \, \text{m}^2 \).

Let me know if you'd like a detailed explanation or have any questions! Here are some follow-up questions:

1. How can we compute the area of irregular shapes more efficiently?
2. What are the properties of a trapezoid that help in area calculation?
3. Can the area formula for trapezoids be applied to any quadrilateral?
4. How can dividing complex figures into smaller triangles or trapezoids aid in solving area problems?
5. Why is knowing the height important in calculating the area of trapezoids?

**Tip**: Always try to break down complex shapes into familiar geometric figures like triangles or trapezoids for easier area calculations.

En la figura, determina el área de la región sombreada. Si MC = 2 m; MN = 3 m y ND = 4 m, además AD = 11 m y BC = 9 m.

Determine the area of a shaded region composed of triangles and trapezoids, using geometry formulas and given dimensions such as MC = 2m, MN = 3m, ND = 4m, AD = 11m, and BC = 9m. This problem is suitable for students in Grades 9-11.

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