Math Problem Statement
The star 18 Scorpii's mass is 2.0 ✕ 1030 kg, its radius is 7.0 ✕ 105 km, and it has a rotational period of approximately 23 days. If 18 Scorpii should collapse into a white dwarf of radius 6.5 ✕ 103 km, what would its period (in s) be if no mass were ejected and a sphere of uniform density can model 18 Scorpii both before and after?
Solution
To calculate the new rotational period of the star, we can apply the conservation of angular momentum principle. Angular momentum is conserved because there is no external torque acting on the system. The formula for angular momentum is:
Where:
- is the moment of inertia of a sphere, ,
- is the angular velocity, , with as the rotational period.
Since angular momentum is conserved:
Expanding this:
The mass and the constants and cancel out, leaving:
Rearranging for :
Substituting the known values:
- ,
- ,
- .
Final Answer:
The new rotational period would be approximately 170.3 seconds.
Would you like a deeper explanation or have additional questions?
Related Questions:
- How is angular momentum conserved in astrophysical phenomena?
- What assumptions are made when modeling stars as spheres of uniform density?
- How does the conservation of angular momentum apply to other collapsing objects like neutron stars?
- What would happen if the star ejected mass during collapse?
- How do scientists measure the rotational period of stars?
Tip: Always check units when solving astrophysical problems to ensure accuracy!
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Math Problem Analysis
Mathematical Concepts
Physics
Angular Momentum Conservation
Rotational Dynamics
Formulas
L = I ⋅ ω
I = (2/5) M R^2
ω = 2π/T
R_initial^2 / T_initial = R_final^2 / T_final
Theorems
Conservation of Angular Momentum
Suitable Grade Level
Undergraduate Physics or Advanced High School Physics
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