https://file.aiquickdraw.com/mathbot/file/172858089674331zlg85p.jpg

To solve the problem in the image, we can use **Ohm's Law**, which is expressed as:

\[
R = \frac{V}{I}
\]

Where:
- \( R \) is the resistance (in ohms, Ω),
- \( V \) is the voltage (in volts, V),
- \( I \) is the current (in amperes, A).

### Given dataTo solve the problem in the image, we can use **Ohm's Law**, which is expressed as:

\[
R = \frac{V}{I}
\]

Where:
- \( R \) is the resistance (in ohms, Ω),
- \( V \) is the voltage (in volts, V),
- \( I \) is the current (in amperes, A).

### Given 
- The current (\( I \)) is 0.25 A.
- The voltage (\( V \)) is 6 V.

Substitute these values into the Ohm's Law formula:

\[
R = \frac{6 \, \text{V}}{0.25 \, \text{A}} = 24 \, \Omega
\]

Thus, the resistance of the lamp is **24 ohms**.

The correct answer is:
- **d. 24 ohm**

Would you like more details or have any questions?

Here are 5 related questions:
1. What is the relationship between voltage, current, and resistance in a circuit?
2. How would the resistance change if the current increased while the voltage remained constant?
3. What would happen to the resistance if the voltage doubled but the current stayed the same?
4. How can Ohm's Law be used in more complex circuits, such as those with multiple resistors?
5. Why is it important to know the resistance in electrical components like lamps?

**Tip:** When solving for electrical resistance, ensure the units for voltage and current are compatible with Ohm's Law (volts for \( V \) and amperes for \( I \)).

Jika amperemeter menunjukkan kuat arus 0,25 A dan voltmeter menunjukkan tegangan 6 volt, hambatan lampu adalah ....

Learn how to calculate the resistance of a lamp using Ohm's Law. Given a current of 0.25 A and a voltage of 6 V, this problem demonstrates the key concepts of electricity, including the formula R = V / I. Suitable for students in Grades 7-9.

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