https://file.aiquickdraw.com/mathbot/file/1727064437437xuaw88hw.jpg

To solve this problem, we need to calculate the total area of the lot and subtract the area occupied by the house to find the area left over.

### Step 1: Find the area of the lot
The lot is a rectangle with dimensions 60 m by 36 m. The area of a rectangle is given by:

\[
\text{Area of lot} = \text{length} \times \text{width} = 60 \, \text{m} \times 36 \, \text{m} = 2160 \, \text{m}^2
\]

### Step 2: Find the area of the house
The house is also a rectangle with dimensions 23 m by 8 m. The area of the house is:

\[
\text{Area of house} = 23 \, \text{m} \times 8 \, \text{m} = 184 \, \text{m}^2
\]

### Step 3: Calculate the area left over
Now, subtract the area of the house from the area of the lot:

\[
\text{Area left over} = \text{Area of lot} - \text{Area of house} = 2160 \, \text{m}^2 - 184 \, \text{m}^2 = 1976 \, \text{m}^2
\]

### Final Answer:
The area left over is **1976 m²**.

Would you like more details on any of these steps, or do you have any questions?

Here are 5 related questions to consider:
1. How do you calculate the perimeter of the lot?
2. What if the house was expanded by 5 meters in width—what would the new area left over be?
3. How much space would remain if multiple houses of the same size were built on the lot?
4. What would the area left over be if part of the lot was reserved for a garden measuring 10 m by 15 m?
5. How would the result change if the house had irregular dimensions (e.g., L-shaped)?

**Tip**: When solving area problems, always remember that subtracting the area of smaller sections from the total gives the remaining usable space!

A lot is 60 m by 36 m. A house 23 m by 8 m is built on the lot. How much area is left over?

Learn how to find the remaining area when a house of dimensions 23 m by 8 m is built on a lot of 60 m by 36 m. The solution involves basic area calculation using the formula for the area of a rectangle. Suitable for students in Grades 5-7.

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