Consider the following data, which indicates the State of a set of clients from a company, and the corresponding Table of Frequencies. Then, answer the following question:

The value of **relative frequency m** is: **___**

(Note: For relative frequencies, insert the value as a percentage (insert only the number, not the symbol. For instance, insert **20** if your answer is 20%).

**ID Number of the client**

**State**

1014

VT

1015

NH

1016

NH

1017

VT

1018

VT

1019

MA

1020

MA

1021

VT

1022

NH

1023

VT

1024

GA

1025

FL

1026

NH

1027

VT

1028

CA

1029

FL

1030

AL

1031

AL

1032

VT

1033

GA

To determine the **relative frequency m**, we'll first need to calculate the frequency distribution for each state and then calculate the relative frequency for each state as a percentage.

### Step 1: Frequency of Each State
Count the occurrences of each state from the client dataTo determine the **relative frequency m**, we'll first need to calculate the frequency distribution for each state and then calculate the relative frequency for each state as a percentage.

### Step 1: Frequency of Each State
Count the occurrences of each state from the client 

| State | Frequency |
|-------|-----------|
| VT    | 6         |
| NH    | 4         |
| MA    | 2         |
| GA    | 2         |
| FL    | 2         |
| AL    | 2         |
| CA    | 1         |

### Step 2: Total Number of Clients
The total number of clients is the sum of all frequencies:
\[
6 + 4 + 2 + 2 + 2 + 2 + 1 = 19
\]

### Step 3: Calculate the Relative Frequency for Each State
The relative frequency for each state is calculated using the formula:
\[
\text{Relative Frequency} = \left(\frac{\text{Frequency of State}}{\text{Total Number of Clients}}\right) \times 100
\]

Let's calculate this for each state:

- **VT**: \(\frac{6}{19} \times 100 \approx 31.58\)
- **NH**: \(\frac{4}{19} \times 100 \approx 21.05\)
- **MA**: \(\frac{2}{19} \times 100 \approx 10.53\)
- **GA**: \(\frac{2}{19} \times 100 \approx 10.53\)
- **FL**: \(\frac{2}{19} \times 100 \approx 10.53\)
- **AL**: \(\frac{2}{19} \times 100 \approx 10.53\)
- **CA**: \(\frac{1}{19} \times 100 \approx 5.26\)

### Answer
The value of **relative frequency m** for each state can be provided by selecting the appropriate state from these calculations, assuming m corresponds to one of these frequencies.

If "m" refers to **NH** (based on an assumption that "m" might refer to NH's frequency), then:
\[
\text{Relative Frequency of NH} = 21
\]

Would you like to clarify which state "m" refers to, or should we proceed with this assumption?

---

**Follow-up Questions:**
1. How would the relative frequencies change if a new state was added with an additional client?
2. How is relative frequency different from cumulative frequency?
3. Can we determine the cumulative frequency for each state with this data?
4. What would be the mode of the states in this data set?
5. How would we calculate the relative frequency if we were only interested in states with frequencies greater than 2?

**Tip:** When converting a relative frequency to a percentage, remember to multiply by 100 to obtain the correct percentage value.

Consider the following data, which indicates the State of a set of clients from a company, and the corresponding Table of Frequencies. Then, answer the following question:

The value of relative frequency m is: ___

(Note: For relative frequencies, insert the value as a percentage (insert only the number, not the symbol. For instance, insert 20 if your answer is 20%).

**ID Number of the client**

**State**

1014 VT

1015 NH

1016 NH

1017 VT

1018 VT

1019 MA

1020 MA

1021 VT

1022 NH

1023 VT

1024 GA

1025 FL

1026 NH

1027 VT

1028 CA

1029 FL

1030 AL

1031 AL

1032 VT

1033 GA

Discover how to calculate the relative frequency for a set of client data states, using frequency distribution and percentage calculations. This exercise is ideal for students in Grades 6-8, focusing on finding relative frequency as a percentage.

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