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The problem shows a rate question: calculating the rate in gallons per minute when 2 3/4 gallons are used in 3 2/3 minutes.

### Step-by-Step Solution:

1. **Convert the Mixed Numbers to Improper Fractions**:
   - \( 2 \frac{3}{4} = \frac{11}{4} \)
   - \( 3 \frac{2}{3} = \frac{11}{3} \)

2. **Set Up the Rate** (gallons per minute):
   \[
   \text{Rate} = \frac{\text{Gallons}}{\text{Minutes}} = \frac{\frac{11}{4}}{\frac{11}{3}}
   \]

3. **Divide Fractions by Multiplying by the Reciprocal**:
   \[
   \frac{\frac{11}{4}}{\frac{11}{3}} = \frac{11}{4} \times \frac{3}{11}
   \]

4. **Simplify**:
   \[
   = \frac{11 \cdot 3}{4 \cdot 11} = \frac{33}{44} = \frac{3}{4}
   \]

So, the rate is:
\[
\frac{3}{4} \text{ gallons per minute}
\]

Would you like more details or have any questions?

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Here are five related questions to expand your understanding:

1. How do you convert any mixed number to an improper fraction?
2. How do you divide by a fraction in a rate problem?
3. Can you simplify the process if both numerator and denominator have the same factor?
4. How does changing the time affect the gallons per minute rate?
5. What if the numbers were decimals instead of fractions?

**Tip**: When working with fractions, always simplify at each step to make calculations easier.

Learn how to find the rate of 2 3/4 gallons in 3 2/3 minutes. This problem covers converting mixed numbers to improper fractions and dividing fractions to calculate a rate, suitable for students in Grades 6-8.

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