To find the probability $P(8 \text{ or } 4)$, we need to determine the likelihood that the spinner lands on either 8 or 4.

Steps to solve:

1. Count the total sections on the spinner: There are 12 sections (numbered 1 through 12).
2. Identify the favorable outcomes: The spinner needs to land on either the number 8 or 4. There are two favorable outcomes (8 and 4).
3. Calculate the probability: $P(8 \text{ or } 4) = \frac{\text{Number of favorable outcomes}}{\text{Total number of sections}} = \frac{2}{12} = \frac{1}{6}$

Answer:

$P(8 \text{ or } 4) = \frac{1}{6}$

Would you like more details or have any questions about this solution?

Here are some related questions for further exploration:

1. What is the probability of landing on an even number?
2. What is the probability of landing on a prime number?
3. What is the probability of landing on a number greater than 6?
4. What is the probability of landing on a single-digit number?
5. How does the probability change if another number is added as a favorable outcome?

Tip: When calculating probabilities with "or" events, count each favorable outcome only once, even if multiple favorable numbers are requested.