The problem asks to find the probability of landing on either 4 or 6 when using the spinner, which has 12 equal sections numbered from 1 to 12.

Step-by-step solution:

1. Total possible outcomes: Since the spinner has 12 equal sections, there are 12 possible outcomes.

2. Favorable outcomes: The favorable outcomes are the numbers 4 and 6, which correspond to two sections. So, there are 2 favorable outcomes.

3. Probability formula: The probability of an event is calculated by the formula: $P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

4. Substitute values: For this problem: $P(4 \text{ or } 6) = \frac{2}{12} = \frac{1}{6}$

Final Answer:

The probability $P(4 \text{ or } 6) = \frac{1}{6}$.

Would you like further details or have any questions?

Here are 5 related questions to consider:

1. What is the probability of landing on an even number on the spinner?
2. How would the probability change if the spinner had 8 sections instead of 12?
3. What is the probability of landing on a number greater than 6?
4. How many possible outcomes would there be if two consecutive spins were done?
5. If the spinner is spun 3 times, what is the probability of landing on 4 exactly once?

Tip: When calculating probabilities, always make sure to count the favorable outcomes correctly and check if all outcomes are equally likely!