Math Problem Statement
Solution
The spinner in the image is divided into 8 equal sections, labeled with the numbers 1, 2, 3, and 4. Let's analyze the distribution of these numbers:
- Number 1 appears twice.
- Number 2 appears once.
- Number 3 appears twice.
- Number 4 appears twice.
Analysis of Each Statement
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You are equally likely to spin a 3 as spin a 4.
- True: Both 3 and 4 each have 2 sections, so the probability of spinning a 3 or a 4 is the same.
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You are 3 times more likely to spin a 3 than a 1.
- False: Both 3 and 1 have the same number of sections (2 each), so they have equal probability.
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The sample space of the spinner is {1, 1, 1, 2, 3, 3, 4, 4}.
- False: The correct sample space is {1, 1, 2, 3, 3, 4, 4}.
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You are more likely to spin a 2 than a 3.
- False: There is only 1 section for 2, while there are 2 sections for 3, making 3 more likely than 2.
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You are equally likely to spin an even or odd number.
- True: There are 4 sections with even numbers (two 4's and one 2) and 4 sections with odd numbers (two 1's and two 3's), so they are equally likely.
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Spinning a 1 is more likely than spinning any other number.
- False: Both 1, 3, and 4 appear twice, so they all have the same probability.
Correct Answers
The three statements that are true about the spinner are:
- You are equally likely to spin a 3 as spin a 4.
- You are equally likely to spin an even or odd number.
Would you like more details or have further questions?
Here are 5 related questions that may enhance your understanding:
- How do we calculate probabilities based on the number of sections?
- What would happen if we added one more section with a new number?
- How can we determine the sample space in different probability setups?
- What is the probability of landing on a specific number if the sections are not congruent?
- How do even and odd probabilities change with different numbers?
Tip: Always count the frequency of each outcome to determine probabilities accurately.
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Math Problem Analysis
Mathematical Concepts
Probability
Sample Space
Event Probability
Formulas
Probability of event = (Number of favorable outcomes) / (Total outcomes)
Theorems
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Suitable Grade Level
Grade 5-7