When a single die is thrown, it has six faces numbered 1 to 6. To find the probability of getting a prime number, let's identify the prime numbers between 1 and 6:

• Prime numbers less than or equal to 6 are: 2, 3, and 5.

Now, let's calculate the probability:

1. Total possible outcomes: 6 (numbers 1 to 6).
2. Favorable outcomes (prime numbers): 3 (2, 3, 5).

The probability $P$ of rolling a prime number is:

$P = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{6} = \frac{1}{2}$

So, the probability of getting a prime number is $\frac{1}{2}$ or 50%.

Would you like a more detailed explanation or have any questions?

Here are some related questions to explore:

1. What is the probability of getting an even number when rolling a die?
2. If two dice are thrown, what is the probability of getting a prime number on both?
3. What is the probability of rolling a composite number on a die?
4. How many prime numbers are there on a standard 12-sided die?
5. What is the probability of rolling a prime number or a 6 on a die?

Tip: Always list out the numbers and identify the prime ones when dealing with probability questions involving primes!