To find the probability of getting a prime number when a die is thrown, we first need to identify the prime numbers on a standard 6-sided die. The numbers on a standard die are: 1, 2, 3, 4, 5, and 6.

Now, let's identify which of these numbers are prime:

• Prime numbers are numbers greater than 1 that are only divisible by 1 and themselves.
• The prime numbers between 1 and 6 are 2, 3, and 5.

Thus, the prime numbers on the die are: 2, 3, 5.

Probability Calculation:

• The total number of possible outcomes when throwing a die = 6.
• The number of favorable outcomes (prime numbers) = 3 (since the prime numbers are 2, 3, and 5).

So, the probability of getting a prime number is: $P(\text{prime}) = \frac{\text{Number of prime numbers}}{\text{Total outcomes}} = \frac{3}{6} = \frac{1}{2}$

Thus, the probability of getting a prime number when a die is thrown is 1/2 or 50%.

Would you like more details or have any questions?

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Here are 5 related questions for you to consider:

1. What is the probability of getting an even number when a die is thrown?
2. What is the probability of getting a number greater than 4 on a die?
3. What is the probability of not getting a prime number on a die?
4. How would the probability change if you were using an 8-sided die?
5. What are the odds of getting a 6 on a standard die?

Tip: When calculating probabilities, always ensure the total number of possible outcomes and the number of favorable outcomes are clearly defined.