Math Problem Statement

Solution

The problem is about a statistical analysis of income (in ten thousand units) after promoting exports in a certain area, using sample statistics to make inferences.

Let's break down the problem:

  • Given:

    • The sample mean of the post-promotion income Xˉ=2.1\bar{X} = 2.1.
    • The sample variance s2=0.01s^2 = 0.01.
    • The normal distribution of the post-promotion income XX in the area follows N(1.8,0.12)N(1.8, 0.12).
  • Tasks:

    1. Determine if the statement P(Y>2)P(Y > 2) (where YY is from N(Xˉ,s2)N(\bar{X}, s^2)) is true for given probabilities.
  • Assumptions:

    • YY is normally distributed as N(Xˉ,s2)N(\bar{X}, s^2), so YN(2.1,0.01)Y \sim N(2.1, 0.01).
    • The value ZZ follows the distribution N(μ,σ2)N(\mu, \sigma^2).

Let's solve it:

Step-by-Step Solution

  1. Calculate the probability P(Y>2)P(Y > 2):

    Given that YN(2.1,0.01)Y \sim N(2.1, 0.01), we need to find the probability that YY exceeds 2.

    The Z-score formula is: Z=YμσZ = \frac{Y - \mu}{\sigma}

    Here, μ=2.1\mu = 2.1 and σ=0.01=0.1\sigma = \sqrt{0.01} = 0.1.

    Calculate the Z-score for Y=2Y = 2: Z=22.10.1=0.10.1=1Z = \frac{2 - 2.1}{0.1} = \frac{-0.1}{0.1} = -1

  2. Find the corresponding probability:

    Using the Z-score table or standard normal distribution table:

    P(Z>1)=1P(Z1)P(Z > -1) = 1 - P(Z \leq -1) The value for P(Z1)0.1587P(Z \leq -1) \approx 0.1587.

    Thus, P(Z>1)=10.1587=0.8413P(Z > -1) = 1 - 0.1587 = 0.8413

  3. Conclusion:

    The probability P(Y>2)0.8413P(Y > 2) \approx 0.8413.

This value of 0.8413 indicates that the correct answer should be:

  • (D) P(Y>2)<0.8P(Y > 2) < 0.8 is false because P(Y>2)=0.8413P(Y > 2) = 0.8413.
  • Therefore, (A) P(X>2)=0.2P(X > 2) = 0.2 is also false since P(Y>2)=0.8413P(Y > 2) = 0.8413.
  • (B) P(X>2)<0.5P(X > 2) < 0.5 is false because P(Y>2)>0.5P(Y > 2) > 0.5.
  • (C) P(Y>2)<0.8P(Y > 2) < 0.8 is true because P(Y>2)=0.8413P(Y > 2) = 0.8413.

Final Answer

The correct choice is:

None of the choices accurately reflect P(Y>2)=0.8413 but if choices were provided correctly, choose based on calculations.\text{None of the choices accurately reflect } P(Y > 2) = 0.8413 \text{ but if choices were provided correctly, choose based on calculations.}

Questions you can ask:

  1. How to interpret normal distribution in practical scenarios?
  2. What are the applications of Z-scores in statistics?
  3. How to use a Z-score table to find probabilities?
  4. What assumptions are made in normal distribution?
  5. How to calculate probabilities for different distributions?

Tip: Always verify your results with standard statistical tables or tools to ensure accuracy in probability calculations.

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Math Problem Analysis

Mathematical Concepts

Statistics
Normal Distribution
Probability

Formulas

Z-score formula: Z = (Y - μ) / σ

Theorems

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Suitable Grade Level

Advanced High School