Math Problem Statement
The perimeter of two squares are 40m and 96m , respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
Solution
Let's denote the side lengths of the first and second squares as and , respectively.
Step 1: Find the side lengths of the squares
The perimeter of a square is given by . So, for the first square:
For the second square:
Step 2: Find the areas of the squares
The area of a square is given by the side length squared. Therefore, the area of the first square is:
The area of the second square is:
Step 3: Find the area of the new square
The problem asks for the perimeter of another square that has an area equal to the sum of the areas of the first two squares. Let's denote the side length of the new square as .
The area of the new square is:
Step 4: Find the side length of the new square
Taking the square root of the area to find the side length :
Step 5: Find the perimeter of the new square
The perimeter of the new square is:
Thus, the perimeter of the square equal in area to the sum of the first two squares is 104 meters.
Would you like more details or have any questions?
Here are five related questions:
- What is the area of the square with a perimeter of 104 meters?
- How does the area of a square change if the perimeter is doubled?
- What is the difference in area between two squares if one has a side length twice as long as the other?
- How do you calculate the diagonal of a square given its side length?
- What would be the perimeter of a square whose area is the difference between the areas of the two original squares?
Tip: When solving problems involving squares, remember that the relationship between the side length and the perimeter or area is quadratic. This can help in quickly checking your results.
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Math Problem Analysis
Mathematical Concepts
Geometry
Quadratic Equations
Formulas
Perimeter of a square: 4 * side length
Area of a square: side length^2
Pythagorean theorem
Theorems
Pythagorean theorem
Suitable Grade Level
Grades 7-9