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The given shape is a rhombus, which has four equal sides. The formula to calculate the perimeter of a rhombus is:

\[
\text{Perimeter} = 4 \times \text{side length}
\]

To find the side length, we can use the Pythagorean theorem because a rhombus is symmetric, and the diagonals of a rhombus bisect each other at right angles. The diagonals are given as 48 m and 20 m.

Since each diagonal is divided in half at the center, half of the diagonals are:
- Half of 48 m = \( \frac{48}{2} = 24 \) m
- Half of 20 m = \( \frac{20}{2} = 10 \) m

Now, we can use the Pythagorean theorem to calculate the side length of the rhombus:

\[
\text{side}^2 = (24)^2 + (10)^2
\]
\[
\text{side} = \sqrt{24^2 + 10^2} = \sqrt{576 + 100} = \sqrt{676} = 26 \, \text{m}
\]

Now that we know the side length is 26 meters, the perimeter is:

\[
\text{Perimeter} = 4 \times 26 = 104 \, \text{m}
\]

Thus, the perimeter of the rhombus is **104 meters**.

Would you like any further details on this solution?

Here are 5 related questions:
1. How would you calculate the area of this rhombus?
2. What is the difference between a rhombus and a square?
3. How does the Pythagorean theorem apply in other geometric shapes?
4. Can a rhombus have right angles?
5. How are the diagonals of a rhombus related to its symmetry?

**Tip:** When working with a rhombus, always remember that the diagonals bisect each other at right angles and can be used to form right triangles.

Calculate the perimeter of the following shape (rhombus with diagonals of 48 m and 20 m).

Learn how to calculate the perimeter of a rhombus with diagonals measuring 48 m and 20 m. This solution uses the Pythagorean theorem to determine the side length and find the perimeter. Ideal for students in Grades 6-8 studying geometry and properties of shapes.

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