To find the period $T$ of the pendulum, we use the given formula:

$T = 2\pi \sqrt{\frac{L}{g}}$

where:

• $L = 0.43$ m (pendulum length)
• $g = 9.81$ m/s² (acceleration due to gravity)

Calculation:

$T = 2\pi \sqrt{\frac{0.43}{9.81}}$

Let’s compute this. math

Given values

L = 0.43 # meters g = 9.81 # m/s^2

Compute period

T = 2 * math.pi * math.sqrt(L / g) TThe period of the pendulum is approximately 1.32 seconds.

Would you like a step-by-step breakdown of the calculation?

Here are some related questions to explore:

1. How does the period change if the pendulum length is doubled?
2. What happens to the period if the acceleration due to gravity decreases?
3. Can this formula be used for a pendulum on the Moon?
4. How does air resistance affect the actual period of a pendulum?
5. What assumptions are made in deriving the pendulum period formula?

Tip: The period of a pendulum is independent of its mass; it only depends on its length and gravity!