Math Problem Statement
A room that looks like the picture has dimensions of 4m * 3m * 3m with a window size of 60 cm x 40 cm, and a door size of 70cm * 200 cm. The walls of the room will be repainted, if 1 can of paint can be used for 6m ^ 2, determine the minimum number of cans of paint needed!
Solution
To determine the minimum number of paint cans needed, we can follow these steps:
Step 1: Calculate the total surface area of the walls
The room has 4 walls, and two dimensions are given:
- Two walls of size:
- Two walls of size:
For the two larger walls:
For the two smaller walls:
Step 2: Calculate the area of the window and door
The window size is , which we convert to meters:
The door size is , which we convert to meters:
Step 3: Calculate the total paintable area
The total surface area of the walls is:
Subtract the area of the window and door:
Step 4: Calculate the number of paint cans needed
Each can of paint covers 6 square meters, so we divide the total paintable area by the coverage of one can: Since we can't buy a fraction of a can, we round up:
Conclusion:
The minimum number of paint cans needed is 7.
Would you like further clarification or details on any part of the process?
Here are 5 related questions:
- How would the calculation change if the window or door sizes were different?
- What would happen if the coverage of each paint can changed?
- How does the shape of the room impact the paint required?
- How would we account for ceilings or floors in a full painting job?
- What methods could reduce the total amount of paint needed?
Tip: When calculating areas for painting, always remember to exclude non-paintable surfaces like windows and doors.
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Math Problem Analysis
Mathematical Concepts
Geometry
Area Calculation
Unit Conversion
Formulas
Area of a rectangle = length * width
Total paintable area = total wall area - (window area + door area)
Number of cans = total paintable area / coverage per can
Theorems
-
Suitable Grade Level
Grades 6-8
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