Math Problem Statement

Severin works in a factory that produces steel bolts. One type of steel bolt should have a mass of 5 g; however, there is some variation, so each bolt may be heavier or lighter by as much as 1.9%. Severin puts together a box of these bolts and notices that the total mass of the bolts in the box is exactly 1 kg. Determine the minimum and maximum number of bolts that could be in the box.

Solution

Let's define the variables and solve the problem step by step.

Given:

  • The expected mass of each bolt is 5g5 \, \text{g}.
  • The mass variation is up to ±1.9%\pm 1.9\%. This means each bolt's mass can range between 5×(10.019)g5 \times (1 - 0.019) \, \text{g} and 5×(1+0.019)g5 \times (1 + 0.019) \, \text{g}.
  • The total mass of bolts in the box is 1kg=1000g1 \, \text{kg} = 1000 \, \text{g}.

We need to find the minimum and maximum number of bolts that could be in the box.

Step 1: Determine the mass range of a single bolt

The mass of a bolt can range from:

Minimum mass per bolt=5×(10.019)=5×0.981=4.905g\text{Minimum mass per bolt} = 5 \times (1 - 0.019) = 5 \times 0.981 = 4.905 \, \text{g}

Maximum mass per bolt=5×(1+0.019)=5×1.019=5.095g\text{Maximum mass per bolt} = 5 \times (1 + 0.019) = 5 \times 1.019 = 5.095 \, \text{g}

Step 2: Calculate the minimum and maximum number of bolts

Now, calculate the number of bolts for each case:

Maximum number of bolts (when each bolt is as light as possible):

Number of bolts=Total massMinimum mass per bolt=10004.905203.86\text{Number of bolts} = \frac{\text{Total mass}}{\text{Minimum mass per bolt}} = \frac{1000}{4.905} \approx 203.86 Since the number of bolts must be an integer, we round down to get 203203 bolts.

Minimum number of bolts (when each bolt is as heavy as possible):

Number of bolts=Total massMaximum mass per bolt=10005.095196.27\text{Number of bolts} = \frac{\text{Total mass}}{\text{Maximum mass per bolt}} = \frac{1000}{5.095} \approx 196.27 Rounding down gives 196196 bolts.

Conclusion:

  • The minimum number of bolts is 196196.
  • The maximum number of bolts is 203203.

Would you like further details on any part of the calculation or concept?

Here are some related questions to explore further:

  1. How would the answer change if the variation was ±2%?
  2. How would you calculate the total mass if you know the number of bolts?
  3. What would happen if the total mass was 1.5 kg instead of 1 kg?
  4. How can we express this problem using inequalities?
  5. What would be the effect of using bolts with different masses?

Tip: When solving word problems, always start by translating the given information into mathematical equations or inequalities!

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Math Problem Analysis

Mathematical Concepts

Percentages
Inequalities
Algebra

Formulas

Mass variation formula: Mass × (1 ± Percentage)
Number of bolts = Total mass / Mass per bolt

Theorems

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Suitable Grade Level

Grades 9-12