Math Problem Statement

Severin works in a factory that produces steel bolts. One type of steel bolt should have a mass of 5 g; however, there is some variation, so each bolt may be heavier or lighter by as much as 1.9%. Severin puts together a box of these bolts and notices that the total mass of the bolts in the box is exactly 1 kg. Determine the minimum and maximum number of bolts that could be in the box.

Solution

The problem states that Severin works in a factory where the bolts have a nominal mass of 5 grams each, but each bolt's mass can vary by up to ±1.9%. The total mass of the bolts in the box is exactly 1 kg (1000 grams). We are asked to determine the minimum and maximum number of bolts that could be in the box.

Step 1: Calculate the mass range for a single bolt

The mass of each bolt can vary by 1.9%. The nominal mass is 5 grams, so:

  • Maximum mass of one bolt: 5g+1.9%×5g=5+0.095=5.095g5 \, \text{g} + 1.9\% \times 5 \, \text{g} = 5 + 0.095 = 5.095 \, \text{g}

  • Minimum mass of one bolt: 5g1.9%×5g=50.095=4.905g5 \, \text{g} - 1.9\% \times 5 \, \text{g} = 5 - 0.095 = 4.905 \, \text{g}

Step 2: Determine the number of bolts in the box

We know the total mass of the bolts is 1000 grams.

  • Maximum number of bolts: The maximum number of bolts would occur if each bolt had the minimum possible mass, 4.905g4.905 \, \text{g}. The number of bolts, nn, would be: n=1000g4.905g203.86n = \frac{1000 \, \text{g}}{4.905 \, \text{g}} \approx 203.86 Since nn must be a whole number, we round this down to 203203 bolts.

  • Minimum number of bolts: The minimum number of bolts would occur if each bolt had the maximum possible mass, 5.095g5.095 \, \text{g}. The number of bolts would be: n=1000g5.095g196.24n = \frac{1000 \, \text{g}}{5.095 \, \text{g}} \approx 196.24 We round this down to 196196 bolts.

Final Answer:

  • Minimum number of bolts: 196
  • Maximum number of bolts: 203

Would you like further clarification or details on this problem?


Here are 5 related questions to expand your understanding:

  1. How would the solution change if the variation in mass was ±2% instead of ±1.9%?
  2. What would happen if the total mass of the bolts was not exactly 1 kg but 2 kg?
  3. Can you calculate the total mass for a specific number of bolts with average mass variations?
  4. How would the problem change if the percentage variation was not symmetric (i.e., +1.9% but −1.5%)?
  5. How could you solve this if the bolts were packed in groups, and each group's mass varied?

Tip: When calculating variations, always consider the range and ensure your results are properly rounded to reflect real-world scenarios (e.g., whole number of objects like bolts).

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Math Problem Analysis

Mathematical Concepts

Percentage
Weight Distribution
Division
Bounds

Formulas

Maximum mass of one bolt: 5g + (1.9% of 5g) = 5.095g
Minimum mass of one bolt: 5g - (1.9% of 5g) = 4.905g
Total mass / Mass per bolt = Number of bolts

Theorems

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Suitable Grade Level

Grades 8-10